Answer: The ends of a magnet are called the poles. Each magnet has a north pole and south pole.
What happens to the image when u make the hole bigger in a pinhole camera?
2 answers:
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Answer:
The current in second wire is 5.0 A.
(B) is correct option.
Explanation:
Given that,
Current in first wire = 3.7 A
Distance = 8.0 cm
We need to calculate the magnetic field due to the current carrying wire
Using formula of magnetic field
Where, I = current
r = distance
Put the value into the formula
For first wire
...(I)
For second wire,
The distance is 8-3.7 = 4.3 cm
...(II)
The magnetic field in both the wires,
From equation (I) and (II)
Hence, The current in second wire is 5.0 A.
The total time it takes the sound to reach our on top of the cliff (10.0 s) is actually sum of two times:
- the time it takes the rock to hit the ground starting from the top of the cliff, t1
- the time it takes the sound to reach the top of the cliff starting from the ground, t2
1) The rock moves by uniformly accelerated motion, with constant acceleration
. Its law of motion is given by 
, where 
is the initial velocity of the rock, and h is the height of the cliff. The time t1 is the time at which the rock reaches the ground, so that y(t1)=0, and the equation becomes
2) The sound moves from the ground to the top of the cliff by uniform motion, with constant speed v=343 m/s. Therefore, the sound covers the distance h (the height of the cliff) in a time t2 given by
3) If we rewrite h in both equations, we can write:
(1)
4) We also know that the sum of t1 and t2 is equal to 10 seconds:
from which we find
if we substitute this into eq.(1), we get
Numerically:
Solving the equation, we find the solution
(the other solution is negative, so it does not have physical meaning). As a consequence,
and the height of the cliff is given by
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- the time it takes the rock to hit the ground starting from the top of the cliff, t1
- the time it takes the sound to reach the top of the cliff starting from the ground, t2
1) The rock moves by uniformly accelerated motion, with constant acceleration
2) The sound moves from the ground to the top of the cliff by uniform motion, with constant speed v=343 m/s. Therefore, the sound covers the distance h (the height of the cliff) in a time t2 given by
3) If we rewrite h in both equations, we can write:
4) We also know that the sum of t1 and t2 is equal to 10 seconds:
from which we find
if we substitute this into eq.(1), we get
Numerically:
Solving the equation, we find the solution
and the height of the cliff is given by
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