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aleksklad [387]
3 years ago
7

The pedals on a bicycle give a mechanical advantage by allowing you to turn the pedals a __________ distance to turn the _______

___ circumstance of the wheels.
Physics
2 answers:
denpristay [2]3 years ago
6 0
Short distance to turn the circumference of the wheels. Mechanical advantage is load/effort I think
Goshia [24]3 years ago
3 0

Answer:

C. Short, larger

Explanation:

It's the correct answer on USA test prep.

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Do you think you could give me the answers to #29?
Vinil7 [7]

reaction, opposite directions, and more

6 0
4 years ago
Read 2 more answers
Dr. John Paul Stapp was U.S. Air Force officer who studied the effects of extreme deceleration on the human body. On December 10
Mars2501 [29]

Answer:

a) a=5.7551 \times g

b) d=20.5539\times g

Explanation:

Given:

  • speed of rocket initially, v_i=0\ m.s^{-1}
  • top speed of rocket after acceleration, v=282\ m.s^{-1}
  • time taken to get to the top speed, t_i=5\ m.s^{-1}
  • final speed of the rocket, v_f=0\ m.s^{-1}
  • time taken to get to the final speed after reaching the top speed, t_f=1.4\ s

Now the acceleration:

a=\frac{v-v_i}{t_i}

a=\frac{282-0}{5}

a=56.4\ m.s^{-2}

Now as a fraction of gravity:

a=\frac{56.4}{9.8}\times g

a=5.7551 \times g

Now, the deceleration:

d=\frac{0-282}{1.4}

d=201.4285\ m.s^{-2}

Now as a fraction of gravity:

d=\frac{201.4285}{9.8}\times g

d=20.5539\times g

6 0
3 years ago
Pls help me very very fast
valentinak56 [21]

Answer:

i think its false

Explanation:

5 0
3 years ago
Review. An electron moves in a circular path perpendicular to a constant magnetic field of magnitude 1.00 mT . The angular momen
Ghella [55]

The speed of an electron when it moves in a circular path perpendicular to a constant magnetic field is 8.88 x 10^7 m/s.

The angular momentum(L) of an electron moving in a circular path is given by the formula,

L = mvr ........(i)

We know that the radius of the path of an electron in a magnetic field is

r = mv/qB

Putting this value in equation (i),

L = mv x mv/qB

or L = (mv)^2/qB

Putting the given values in the above equation,

4 x 10^-25 = (9.1x10^-31)^2 x v^2/ 1.6 x 10^-19 x 1 x 10^-3

v comes out to be 8.88 x 10^7 m/s.

Hence, the speed of an electron when it moves in a circular path perpendicular to a constant magnetic field is 8.88 x 10^7 m/s.

To know more about "angular momentum", refer to the following link:

brainly.com/question/15104254?referrer=searchResults

#SPJ4

5 0
2 years ago
When light passes from a faster medium into a slower medium, which of the following explains what will occur?
beks73 [17]

When light passes from a faster medium into a slower medium, light will be refracted toward a line drawn perpendicular to the point of refraction. <em>(B)</em>

5 0
4 years ago
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