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ollegr [7]
3 years ago
11

If you want to make a strong battery, should you pair two metals with high electron affinities, low electron affinities, or a mi

x? Explain your answer.
Physics
1 answer:
zalisa [80]3 years ago
6 0

A mix

Explanation:

A battery is an electrochemical cell that converts chemical energy into electrical energy. The chemical reactions in a battery ensures that current is produced.

  • A battery is made up of two electrodes which are the cathode and anode.
  • The cathode is the positive electrode and the anode is the negative one.
  • These electrodes are made up of metals.
  • Electrons moves from the anode to the cathode and current flows from cathode to anode.
  • At the anode oxidation occurs because electrons are produced here.
  • It needs to have low electron affinity.
  • At the cathode where reduction occurs, the electron affinity must be high.
  • This is the driving force for the production of electricity in electrochemical cells.

Learn more:

Battery brainly.com/question/8892837

#learnwithBrainly

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If all this energy is added to 50 kg of water (the amount of water in a 165-lb person) at 37 ∘C, what is the final state of the
Reika [66]

Answer:

Vapors

Explanation:

We take into account that all the energy from the lightning has been transformed into steam.

\Delta U = Q -  W\\Q = mC \Delta T\\Q = mL

We calculate the amount of energy required by water to convert into steam.

Q_{water} = 50 \times \times 4180 \times (100-37)\\= 1.132 \times 10^7 \ J

Q_{change\ to\ steam} = 50 \times 2.256 \times 106 \\= 1.128 \times 10^8 \ J

Q_{total} = 1.132 \times 10^7 + 1.128 \times 10^8\\= 1.126 \times 10^8 \ J

From the lightning we received 10^{10} \ J of energy, out of which 1.126 \times 10^8 has been used to convert the water into steam.

Energy left = 10^{10} - 1.126 \times 10^8 = 9.88 \times 10^9 \ J

We use this energy to convert steam into vapors.

Q = \Delta E

Q = \Delta E = mc (T_{f} - T{i})\\T_{f} = \frac {\Delta E}{mc} + T_{i}\\ \\T_{f} = 100 + \frac{9.88 \times 10^{10}}{50 \times 1970}\\T_{f} = 100 + 10^8\\T_{f} = 10 ^{ \ 8} \ {^ \circ } C

With this temperature, we can easily interpret that the vapors will be dissociated in hydrogen and oxygen particles.

5 0
3 years ago
Taden has found a table of the atmospheric layers of the Sun. However, he can’t make out the names of the layers in the chart.
Alexeev081 [22]

The sun is a ball of hot gases containing different kinds of elements at different cores. It has a very high temperature that radiates all throughout the Milky Way galaxy. The sun has three main parts; photosphere, chromospheres and corona. The outer core of a star located at the chromospheres contains mostly of hydrogen. Inside the hydrogen is helium then carbon, oxygen, neon, magnesium silicon and the inert gas. The photosphere is scattered by the loose electrons in the corona’s plasma.

4 0
3 years ago
Read 2 more answers
A heat engine takes in 840 kJ per cycle from a heat reservoir. Which is not a possible value of the engine's heat output per cyc
zhannawk [14.2K]
We have by the first law of thermodynamics tha energy is preserved, hence we cannot have over 840kJ per cycle. We have by the laws of thermodynamics (the 2nd one in specific) that the entropy of a system cannot increase. We cannot have an output of  840 kJ per cycle from a heat engine because then that would mean that the entropy would stay the same, while any heat engine increases it. Hence, any value \geq 840 kJ is acceptable.
8 0
3 years ago
How large a net force is required to accelerate a 1600-kg SUV from rest to a speed of 25 m/s in a distance of 200 m
Mars2501 [29]

Answer:

F=2496 N

Explanation:

Given that,

Mass of SUV, m = 1600 kg

Initial speed, u = 0

Final speed, v = 25 m/s

Distance, d = 200 m

We need to find the net force. Firstly, let's find acceleration using equation of motion.

v^2-u^2=2ad\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(25)^2-(0)^2}{2\times 200}\\\\a=1.56\ m/s^2

Net force, F = ma

F=1600\times 1.56\\\\F=2496\ N

So, the net force is 2496 N.

6 0
3 years ago
A car traveling with velocity v is decelerated by a constant acceleration of magnitude a. It travels a distance d before coming
sergeinik [125]

Answer:

D) quadruple.

Explanation:

Assuming the same constant acceleration a in both cases, as we have as givens  the acceleration a, the distance d, and the initial velocity v, we can use the following kinematic equations in order to compare the distances:

vf² - v₀² = 2*a*d

As the final state of the car is at rest, the final velocity vf, is 0.

⇒ - v₀² = 2*(-a)*d ⇒ d =v₀² / 2*a

1) initial velocity v₀

d₁ = v₀² / 2 a

2 ) initial velocity 2*v₀

⇒ d₂ = (2*v₀)² / 2*a = 4*v₀² / 2*a ⇒ d₂ = 4* (v₀² / 2*a)

⇒ d₂ = 4* d₁

As the equation shows, the distance required to stop, if the initial velocity were doubled, the distance required to stop would quadruple.

3 0
3 years ago
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