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Leno4ka [110]
3 years ago
12

Which describes one event that causes an eclipse?

Physics
1 answer:
Burka [1]3 years ago
3 0

Answer:

Earths shadow covering the moon would create a lunar eclipse.

Explanation:

because i just know

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The potential difference between two parallel conducting plates in vacuum is 165 V. An alpha particle with mass of 6.50×10-27 kg
shepuryov [24]

Answer:

kinetic energy (K.E) = 5.28 ×10⁻¹⁷            

Explanation:

Given:

Mass of  α particle (m) = 6.50 × 10⁻²⁷ kg

Charge of  α particle (q) = 3.20 × 10⁻¹⁹ C

Potential difference ΔV = 165 V

Find:

kinetic energy (K.E)

Computation:

kinetic energy (K.E) = (ΔV)(q)

kinetic energy (K.E) = (165)(3.20×10⁻¹⁹)

kinetic energy (K.E) = 528 (10⁻¹⁹)

kinetic energy (K.E) = 5.28 ×10⁻¹⁷              

4 0
3 years ago
The measured value of mass M in an experiment is M = 0.743 ± 0.005kg. The error in 2M is
omeli [17]

Given the measured value of mass M in the experiment the error in 2M is  ; dM

<u>Given data :</u>

Measured value of mass M = ( 0.743 ± 0.005 ) kg

<h3>The error in 2M in the measured value </h3>

The error in 2M in the measured value M = 0.743 ± 0.005 kg is dM while the error in M² will be 2dM

Hence we can conclude that the measured value of mass M in the experiment the error in 2M is  ; dM.

Learn more about error in 2M : brainly.com/question/6650225

8 0
2 years ago
1. How much force would you have to apply to a 15kg object in order to accelerate it!<br> a 2 m/s?
mihalych1998 [28]

30N

Explanation:

Given parameters:

Mass of object = 15kg

Acceleration = 2m/s

Unknown:

Force = ?

Solution:

Force is given as the product of mass and acceleration:

         F = m x a

   m is the mass

    a is the acceleration

Inputting the parameters:

     F = 15 x 2 = 30N

The unit of force is newtons, N .

Learn more:

Force brainly.com/question/10470406

#learnwithBrainly

3 0
3 years ago
In 1985, Said Aouita set the world record for the 1500m race in a time of 3 minute 29.46 second ? What was his average speed ?
Vitek1552 [10]
 but tpla ybut tpla y but tpl but tpla y but tpla y but tpla ya y but tpla y but tpla y
8 0
3 years ago
An 85-kg man plans to tow a 109 000-kg airplane along a runway by pulling horizontally on a cable attached to it. Suppose that h
Lelu [443]

Answer:

The greatest acceleration the man can give the airplane is 0.0059 m/s².

Explanation:

Given that,

Mass of man = 85 kg

Mass of airplane = 109000 kg

Distance = 9.08

Coefficient of static friction = 0.77

We need to calculate the greatest friction force

Using formula of friction

F=\mu mg

Where, m = mass of man

g = acceleration due to gravity

Put the value into the formula

F = 0.77\times85\times9.8

F= 641.41\ N

We need to calculate the acceleration

Using formula of newton's second law

F = ma

a=\dfrac{F}{m}

Put the value into the formula

a=\dfrac{ 641.41}{109000}

a=0.0059\ m/s^2

Hence, The greatest acceleration the man can give the airplane is 0.0059 m/s².

3 0
3 years ago
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