2 years ago

Which describes one event that causes an eclipse?

Physics

1 answer:

Burka [1]2 years ago

3 0

Answer:

Earths shadow covering the moon would create a lunar eclipse.

Explanation:

because i just know

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Caculate the total charge transferred through a wire carrying a current of 0.5 Ameter for a period of 20 seconds.

Marina CMI [18]

charge = current x time = 0.5x 20=10Coulombs

5 0

2 years ago

Anyone tell me what is the physics

Katyanochek1 [597]

Answer:

physic is branch of science in which math is its brother and will deal with the equation,law and evidence of natural phenomenon.

6 0

2 years ago

A rope passes over a fixed sheave with both ends hanging straight down. The coefficient of friction between the rope and sheave

Oliga [24]

Answer:3.51

Explanation:

Given

Coefficient of Friction $\mu =0.4$

Consider a small element at an angle \theta having an angle of $d\theta$

Normal Force $=T\times \frac{d\theta }{2}+(T+dT)\cdot \frac{d\theta }{2}$

$N=T\cdot d\theta$

Friction $f=\mu \times Normal\ Reaction$

$f=\mu \cdot N$

and $T+dT-T=f=\mu Td\theta$

$dT=\mu Td\theta$

$\frac{dT}{T}=\mu d\theta$

$\int_{T_2}^{T_1}\frac{dT}{T}=\int_{0}^{\pi }\mu d\theta$

$\frac{T_2}{T_1}=e^{\mu \pi}$

$\frac{T_2}{T_1}=e^{0.4\times \pi }$

$\frac{T_2}{T_1}==e^{1.256}$

$\frac{T_2}{T_1}=3.51$

7 0

2 years ago

What is the distance traveled when a car goes 20 m/s for 60 seconds?

AfilCa [17]

Answer:

1200 m

Explanation:

s= vt

s= 20m/s × 60 s

s= 1200 m

hope it hepls

for any question comment me ❤❤

5 0

3 years ago

Our eyes are typically 6 cm apart. Suppose you are somewhat unique, and yours are 9.50 cm apart. You see an object jump from sid

Serhud [2]

Answer: 12.67 cm, 8 cm

Explanation:

Given

Normal distance of separation of eyes, d(n) = 6 cm

Distance of separation is your eyes, d(y) = 9.5 cm

Angle created during the jump, θ = 0.75°

To solve this, we use the formula,

θ = d/r, where

θ = angle created during the jump

d = separation between the eyes

r = distance from the object

θ = d/r

0.75 = 9.5 / r

r = 9.5 / 0.75

r = 12.67 cm

θ = d/r

0.75 = 6 / r

r = 6 / 0.75

r = 8 cm

Thus, the object is 12.67 cm far away in your own "unique" eyes, and just 8 cm further away to the normal person eye

8 0

3 years ago