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3 years ago

Is there a link between the number of bulbs and current drawn from the power pack?

Physics

1 answer:

LuckyWell [14K]3 years ago

5 0

Answer:

Yes there is if number of bulb is high the bulbs wouldn't glow much brighter

Explanation:

You might be interested in

Why does the car stop? Where did the energy go?

Viefleur [7K]

Answer:

Because you hit the break?

8 0

2 years ago

Abdominal breathing is a condition in which only the inferior half of the lungs can be seen expanding and contracting with each

lilavasa [31]

Answer:

The correct answer is - Damage to the nerves that control the diaphragm.

Explanation:

Abdominal breathing is a condition in which inferior half of the lungs can be seen relaxing or contracting and expanding with the breath. This condition occurs due to the various conditions that lead to the respiratory.

It is cause due to the damage to nerves that control the diaphragm. The phrenic nerve is one of the nerve of diaphragm initiates in the neck and passes down.

Thus, the correct answer is - Damage to the nerves that control the diaphragm.

The phrenic nerve is a nerve that originates in the neck (C3–C5) and passes down between the lung and heart to reach the diaphragm.

7 0

3 years ago

In this type of polarization a Polaroid filter serves as a device that filters out one-half of the vibrations.

erik [133]

The answer is d.
hope it helped

6 0

3 years ago

A small metal bead, labeled A, has a charge of 28 nC .It is touched to metal bead B, initially neutral, so that the two beads sh

Dmitry_Shevchenko [17]

Answer:

Explanation:

Let the charge on bead A be q nC and the charge on bead B be 28nC - qnC

Force F between them

4.8\times10^{-4} = $\frac{9\times10^9\times q\times(28-q)\times10^{-18}}{(5\times10^{-2})^2}$

=120 x 10⁻⁸ = 9 x q(28 - q ) x 10⁻⁹

133.33 = 28q - q²

q²- 28q +133.33 = 0

It is a quadratic equation , which has two solution

q_A = 21.91 x 10⁻⁹C or q_B = 6.09 x 10⁻⁹ C

3 0

3 years ago

What is the electric field strength between two parallel plates 5cm apart with a potential difference of 25V across them?

Butoxors [25]

Use the following formula for the electric field strength between two parallel plates:

E = V/d

where,

V: potential difference = 25V

d: distance between plates = 5 cm = 0.05 m

Replace the previous values of the parameters into the formula for E:

$E=\frac{25V}{0.05m}=500\frac{V}{m}$

Hence, the electric field strength is 500V/m

5 0

1 year ago