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melamori03 [73]
3 years ago
14

A scientific theory ______.

Physics
1 answer:
NikAS [45]3 years ago
5 0
Its is a wild guess about how something in the universe functions
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If the radius of an object in circular motion is doubled, what change will occur in the centripetal force?
cestrela7 [59]

Answer:

The centripetal force will be 1/2 as big as it was. (option c)

Explanation:

Recall that centripetal force (F_c) is defined as: F_c=m\,* \frac{v^2}{r} where "v" is the tangential velocity of the object in circular motion, "r" is the radius of rotation and "m" is the object's mass.

So if we start with such formula with a given mass, radius, and tangential velocity, and then we move to a situation where everything stays the same except for the radius which doubles, then the new centripetal force (F'_c) will be given by: F'_c=m\,* \frac{v^2}{2r}

and this is half (1/2) of the original force:

F'_c=m\,* \frac{v^2}{2r}\\F'_c=m\,* \frac{v^2}{r}*\frac{1}{2} \\F'_c=F_c\,*\,\frac{1}{2}

which is expressed by option "c" of the provided list.

8 0
3 years ago
Read 2 more answers
What is horoscope? what is its uses
Lemur [1.5K]
What is horoscope?
A forecast of a person's future, typically including delineation of character and circumstances, based on the relative positions of the stars and planets at the time of that person's birth.

   *
A short forecast for people born under a particular sign, especially as published in a newspaper or magazine.
 
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A birth chart.
 

What is its uses?
It can also be calculated for an event, a question, and even a country. Symbols are used to represent planets, signs, and geometric connections called aspects. In most cases, the horoscope in Western astrology is drawn on a circular wheel. 

8 0
4 years ago
Read 2 more answers
A woman fires a rifle with barrel length of 0.5400 m. Let (0, 0) be where the 125 g bullet begins to move, and the bullet travel
dybincka [34]

Answer:

Explanation:

Given that,

Length of barrel =0.54m

Mass of bullet=125g=0.125kg

Force extend

F=16,000+10,000x-26,000x²

a. Work done is given as

W= ∫Fdx

W= ∫(16,000+10,000x-26,000x² dx from x=0 to x=0.54m

W=16,000x+10,000x²/2 -26,000x³/3 from x=0 to x=0.54m

W=16,000x+5,000x²- 8666.667x³ from x=0 to x=0.54m

W= 16,000(0.54) + 5000(0.54²) - 8666.667(0.54³) +0+0-0

W=8640+1458-1364.69

W=8733.31J

The workdone by the gas on the bullet is 8733.31J

b. Work done is given as

Work done when the length=1.05m

W= ∫Fdx

W= ∫(16,000+10,000x-26,000x² dx from x=0 to x=1.05m

W=16,000x+10,000x²/2 -26,000x³/3 from x=0 to x=1.05m

W=16,000x+5,000x²- 8666.667x³ from x=0 to x=1.05mm

W= 16,000(1.05) + 5000(1.05²) - 8666.667(1.05³) +0+0-0

W=16800+5512.5-10032.75

W=12,279.75J

The workdone by the gas on the bullet is 12,279.75J

3 0
4 years ago
Borace drew a diagram to compare the processes of scientific investigation and technological design.
Zepler [3.9K]
The answer is "Conduct an experiment" :)
4 0
4 years ago
Read 2 more answers
A brass cube, 10 cm on a side, is raised in temperature
lana [24]

Answer:

\delta L\%=22.5\%

Explanation:

<em>Assuming that the thermal expansion of brass cube occurs isotropically (i.e. equal in all the directions).</em>

Given:

  • length of the cube, l=10\ cm=0.1\ m
  • change in temperature of the cube, \Deta T=200\^{\circ}C
  • coefficient of volume expansion, \beta=57\times 10^{-6}\ ^{\circ}C^{-1}

<u>Hence volume of the cube:</u>

V=10^{-3}\ m^3

Now the volume of the cube after expansion:

\delta V=V.\beta.\Delta T

\delta V=10^{-3}\times 57\times 10^{-6}\times 200

\delta V=1.14\times 10^{-5}\ m^3

Therefore,

\delta L=0.0225\ m

<u>Now the percentage change in the edges of the cube:</u>

\delta L\%=\frac{\delta L}{L} \times 100

\delta L\%=\frac{0.0225}{0.1} \times 100

\delta L\%=22.5\%

5 0
3 years ago
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