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3 years ago

A book weighing 12 n is placed on a table. how much support force does a table exert on the book?

Physics

1 answer:

Alenkasestr [34]3 years ago

7 0

It should be 12 N. the force of the book on the table should be the same as the force of the table on the book.

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Star A and Star B have different apparent brightnesses but identical luminosities. Star A is 10 light years away from earth and

STALIN [3.7K]

intensity of a star is inversely depends on the square of the distance from the star

we can say it is given as

$\frac{I_1}{I_2} = \frac{r_2^2}{r_1^2}$

here we know that

$\frac{I_1}{I_2} = 36 times$

also we know that

$r_1 = 10 Ly$

now we will have

$\frac{I_1}{I_2} = \frac{r_2^2}{r_1^2}$

$36 = \frac{r_2^2}{10^2}$

$r_2 = 60 Ly$

so other star is at distance 60 Light years

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3 years ago

What are some ways to improve heat islands temperature

Vera_Pavlovna [14]

Answer:

1. Increase shade around your home. Planting trees and other vegetation

2.lowers surface and air temperatures by providing shade and cooling through evapotranspiration.

3.Install green roofs.

4.Install cool roofs.

5.Use energy-efficient appliances and equipment.

6.Check on your friends, family, and neighbors.

Explanation:

3 0

3 years ago

The waste products of a nuclear fusion power plants can be best described as

I am Lyosha [343]

They can be described as small in quantity and very dangerously radioactive.

4 0

3 years ago

Read 2 more answers

In Fig.25-46,how much charge is stored on the parallel-plate capacitors by the 12.0 V battery? One is filled with air,and the ot

Fittoniya [83]

Answer:

$Q=7.9\times 10^{-10}\ C$

Explanation:

Given that

V= 12 V

K=3

d= 2 mm

Area=5.00 $ 10#3 m2

Assume that

$ = Multiple sign

# = Negative sign

$A=5\times 10^{-3}\ m^2$

We Capacitance given as

For air

$C_1=\dfrac{\varepsilon _oA}{d}$

$C_1=\dfrac{8.85\times 10^{-12}\times 5\times 10^{-3}}{2\times 10^{-3}}$

$C_1=2.2\times 10^{-11}\ F$

$C_2=\dfrac{K\varepsilon _oA}{d}$

$C_2=\dfrac{3\times 8.85\times 10^{-12}\times 5\times 10^{-3}}{2\times 10^{-3}}\ F$

$C_2=6.6\times 10^{-11}\ F$

Net capacitance

C=C₁+C₂

$C=8.8\times 10^{-11}\ F$

We know that charge Q given as

Q= C V

$Q=12\times 6.6\times 10^{-11}\ C$

$Q=7.9\times 10^{-10}\ C$

6 0

3 years ago

How many diffraction maxima are contained in a region of the Fraunhofer single-slit pattern, subtending an angle of 2.12°, for a

Luba_88 [7]

Answer:

Explanation:

We are given that

$\theta=2.12^{\circ}$

Slid width,a=0.110 mm= $0.11\times 10^{-3} m$

$1mm=10^{-3} m$

Wavelength, $\lambda=582 nm=582\times 10^{-9}$ m

$1nm=10^{-9} m$

We have to find the number of diffraction maxima are contained in a region of the Fraunhofer single-slit pattern.

$asin\theta=\frac{2N+1}{2}\lambda$

Using the formula

$0.11\times 10^{-3}sin(2.12)=\frac{2N+1}{2}(582\times 10^{-9})$

$2N+1=\frac{0.11\times 10^{-3}sin(2.12)\times 2}{582\times 10^{-9}}$

$2N+1=13.98$

$2N=13.98-1=12.98$

$N=\frac{12.98}{2}\approx 6$

Hence, 6 diffraction maxima are contained in a region of the Fraunhofer single-slit pattern

5 0

3 years ago