We use 1/o + 1/i = 1/f where o is the distance of the object, i as distance of the image and f is the focal length.
Substituting, <span>1/ 100 + 1 / i = - 1 /25 </span>
<span>i = - 20 cm </span>
<span>For the case of the problem,</span>
<span>o = (20 + 30) = 50 cm </span>
<span>f = 33.33. </span>Using 1<span> / i + 1 / o = 1/f , </span><span> </span><span>i = 100 cm </span>
<span>M = magnification = - i / o </span>
<span>m1 = -(-20)/100 = 20/100 = 0.2 </span>
<span>m2 = -100/50 = -2 </span>
<span>M = m1*m2 = -2 x 0.2 = -0.4.</span>
Answer:
<h2>117.6 J</h2>
Explanation:
The gravitational potential energy of a body can be found by using the formula
GPE = mgh
where
m is the mass
h is the height
g is the acceleration due to gravity which is 9.8 m/s²
From the question we have
GPE = 6 × 9.8 × 2
We have the final answer as
<h3>117.6 J</h3>
Hope this helps you
Answer:
n = 1.56
Explanation:
The total reflection attempts occurs when a light beam passes from a medium with a higher index to a medium with a lower nest, at an angle where it occurs we can find them by the refractive relationship
n₁ sin θ₁ = n₂ sin θ₂
n1 = n2 / sin θ₁
For this relationship to be fulfilled, the liquid index must be greater than the air index divided by the sine of the critical angle
Let's use trigonometry to find angle
tan θ = y / x
θ = tan⁻¹ 7.2 / 8.6
θ = 39.94º
n₁ = 1 / sin 39.94
n = 1.56
This is the refractive index of the liquid
I believe it is an electromagnet
Answer:
The distance between the lighthouse and the ship
from the start position A = 5.08 miles
from the Final point B = 7.23 miles
Explanation:
Note: Refer the figure
Let the position of the lighthouse be 'L'
Given:
When the ship is at the position A, ∠DAL=37°
Now, when the ship sails through a distance of 2.5 i.e at position B
mathematically,
AB=2.5 miles
∠ABL=25°
Now,
∠DAL + ∠LAB = 180°
or
37° + ∠LAB = 180°
or
∠LAB = 180° - 37° = 143°
Also, In ΔLAB
∠LAB + ∠ABL + ∠ALB = 180°
or
143° + 25° + ∠ALB = 180°
or
∠ALB = 180° - 143° - 25° = 12°
Now using the concept of the sin law
In ΔLAB
or
AL = 5.08 miles
and,
or
BL = 7.23 miles
hence,
The distance between the lighthouse and the ship
from the start position A = 5.08 miles
from the Final point B = 7.23 miles
