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steposvetlana [31]
3 years ago
7

A race car is accelerating at 5m/s and then speeds up to a final velocity of 12 m/s if the race car driver finished this let of

the race in 6 seconds what was the car's acceleration
Physics
2 answers:
Marina CMI [18]3 years ago
4 0

Answer:

1.167 m/s^2

Explanation:

Given that a race car is accelerating at 5m/s and then speeds up to a final velocity of 12 m/s if the race car driver finished this let of the race in 6 seconds what was the car's acceleration ?

From the question, the following parameters are given

Initial velocity U = 5 m/s

Final velocity V = 12 m/s

Time t = 6 s

According to the definition of acceleration:

Acceleration = change in velocity per time taken.

I.e

Acceleration =( V - U)/ t

Acceleration =( 12 - 5 )/6

Acceleration = 7/6

Acceleration = 1.167 m/s^2

Therefore, acceleration is 1.167 m/s^2

noname [10]3 years ago
3 0

Answer:

the acceleration of the car is 1.167 m/s²

Explanation:

Given;

initial velocity of the race car, u = 5 m/s

final velocity of the race car, v = 12 m/s

time to finish the race, t = 6 s

The acceleration of the car is calculated as;

a = (v - u) / t

a = (12 - 5) / (6)

a = 1.167 m/s²

Therefore, the acceleration of the car is 1.167 m/s²

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Andre45 [30]

This question is incomplete

Complete Question

In the United States, a standard letter-sized piece of paper is 8.5 inches wide by 11 inches long. The international standard for a letter-sized piece of paper is different. The international standard is based on SI units: 21.0 cm wide by 29.7 cm long.

a. Convert 21.0 cm to inches. Show your dimensional analysis setup.

b. Convert 29.7 cm to inches. Show your dimensional analysis setup.

c. State the dimensions, in inches, of the international standard for a letter-sized piece of paper.

d. Which piece of paper is longer: a U.S. letter-sized piece of paper, or an international letter-sized piece of paper?

Answer:

a) 8.267721 inches ≈ 8.3 inches

b) 11.6929197 inches ≈ 11.7 inches

c) It's dimensions in inches for the international standard for letter - sized for paper = 8.3 wide inches by 11.7 inches long

d) The International standard letter - sized paper is longer.

Explanation:

a. Convert 21.0 cm to inches. Show your dimensional analysis setup.

1 cm = 0.393701inch

21 cm =

Cross Multiply

21 cm × 0.393701inch/ 1 cm

= 8.267721 inches

Approximately 8.3 inches

b. Convert 29.7 cm to inches. Show your dimensional analysis setup.

1 cm = 0.393701inch

29.7 cm =

Cross Multiply

29.7 × 0.393701 inch/ 1 cm

= 11.6929197 inches

Approximately 11.7 inches

c. State the dimensions, in inches, of the international standard for a letter-sized piece of paper.

The international standard for a letter-sized has dimensions 21.0 cm wide by 29.7 cm long.

Where

21.0cm = 8.267721 inches

≈ 8.3 inches

29.7cm = 11.6929197 inches

≈ 11.7 inches

Hence, it's dimensions in inches = 8.3 inches by 11.7 inches.

d. Which piece of paper is longer: a U.S. letter-sized piece of paper, or an international letter-sized piece of paper?

U.S letter - sized paper = 8.5 inches wide by 11 inches long

International standard letter- sized paper = 8.3 wide inches by 11.7 inches long.

Hence, the International standard letter - sized paper is longer.

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Explanation:

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Answer:

  v = 54.2 m / s

Explanation:

Let's use energy conservation for this problem.

Starting point Higher

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Final point. Lower

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        Em₀ = Em_{f}

        m g h = ½ m v²

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Let's calculate

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AlladinOne [14]
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Answer:

Option A) n

Explanation:

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