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steposvetlana [31]
3 years ago
7

A race car is accelerating at 5m/s and then speeds up to a final velocity of 12 m/s if the race car driver finished this let of

the race in 6 seconds what was the car's acceleration
Physics
2 answers:
Marina CMI [18]3 years ago
4 0

Answer:

1.167 m/s^2

Explanation:

Given that a race car is accelerating at 5m/s and then speeds up to a final velocity of 12 m/s if the race car driver finished this let of the race in 6 seconds what was the car's acceleration ?

From the question, the following parameters are given

Initial velocity U = 5 m/s

Final velocity V = 12 m/s

Time t = 6 s

According to the definition of acceleration:

Acceleration = change in velocity per time taken.

I.e

Acceleration =( V - U)/ t

Acceleration =( 12 - 5 )/6

Acceleration = 7/6

Acceleration = 1.167 m/s^2

Therefore, acceleration is 1.167 m/s^2

noname [10]3 years ago
3 0

Answer:

the acceleration of the car is 1.167 m/s²

Explanation:

Given;

initial velocity of the race car, u = 5 m/s

final velocity of the race car, v = 12 m/s

time to finish the race, t = 6 s

The acceleration of the car is calculated as;

a = (v - u) / t

a = (12 - 5) / (6)

a = 1.167 m/s²

Therefore, the acceleration of the car is 1.167 m/s²

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The elevator's free-body diagram has three forces, the force of gravity, a downward normal force from you, and an upward force from the tension in the cable holding the elevator. The combined system of you + elevator has two forces, a combined force of gravity and the tension in the cable.

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A hydrogen discharge lamp emits light with two prominent wavelengths: 656 nm (red) and 486 nm (blue). The light enters a flint-g
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The angle between the red and blue light is 1.7°.

Explanation:

Given that,

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Wavelength of blue = 486 nm

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n_{r}=1.572

n_{b}=1.587

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Using Snell's law,

n_{r}\sin\theta_{i}=n_{a}\sin\theta_{r}

Put the value into the formula

1.572\sin37=1\times\sin\theta_{r}

\theta_{r}=\sin^{-1}(\dfrac{1.572\sin37}{1})

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n_{b}\sin\theta_{i}=n_{a}\sin\theta_{b}

Put the value into the formula

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Using formula of angle

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8 0
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A pebble is dropped from rest from the top of a tall cliff and falls 53.4 m after 3.3 s has elapsed. How much farther does it dr
jeka94

Answer:

426.84 m

Explanation:

initial velocity u = 0

time t = 3.3 s

distance travelled s = 53.4 m

acceleration due to gravity = g

s = ut + 1/2 g t²

53.4 = 0 + 1/2 g x 3.3²

g = 9.8 m /s²

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u again = 0

h = .5 x 9.8 x 9.9²

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distance travelled in last 6.6 s

= 480.24 - 53.4

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