What kind of wave (transverse of longitudinal) is each of the following and why?
1 answer:
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Refer to the diagram shown below.
W = 87.5 N, the weight of the sandwiched board.
μ = 0.622, the static coefficient of friction.
From the free body diagram of the sandwiched board, obtain
2μF = W
F = W/(2μ) = 87.5/(2*0.622) = 70.34 N
Answer: 70.34 N
W = 87.5 N, the weight of the sandwiched board.
μ = 0.622, the static coefficient of friction.
From the free body diagram of the sandwiched board, obtain
2μF = W
F = W/(2μ) = 87.5/(2*0.622) = 70.34 N
Answer: 70.34 N
The acceleration of the skier over the distance traveled is 10.38 m/s²
The given parameters;
- Initial velocity of the skier, u = 56 m/s
- Distance covered by the skier, s = 151 m
Acceleration is defined as the change in velocity per change in time of motion.
The magnitude of the acceleration of the skier is calculated as follows;
where;
<em>v is the final velocity at the end of 151 m = 0</em>
Thus, the acceleration of the skier over the distance traveled is 10.38 m/s²
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Answer:
1440 × 10⁴ N/C
Explanation:
Data provided in the question:
Charge density λ1 = 0.6 μC/cm = 6 × 10⁻⁵ C/m
a = 7.5 cm = 0.075 m
Now,
Electric field due to a line charge at a distance 'a' is given as:
Ex(P) =
also,
we know
= 9 × 10⁹ Nm²/C²
Thus,
we have
Ex(P) =
therefore,
Ex(P) =
= 1440 × 10⁴ N/C