3 years ago

Which statement correctly compares sound and light waves

1 answer:

8 0

Answer:

Light waves carry energy parallel to the motion of the wave, while sound waves carry energy perpendicular to it. Sound waves carry energy parallel to the motion of the wave, while light waves carry energy perpendicular to it.

Explanation:

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Given the 1-m stick shown below, which is held by a thread at its center. Block 1 is 15 N held at the 10 cm mark, while block 2

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Jejebsjwiebrirndjdjdjjrkdid

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2 years ago

At what rate is soda being sucked out of a cylindrical glass that is 6 in tall and has radius of 2 in? The depth of the soda dec

evablogger [386]

Answer:

The soda is being sucket out at a rate of 3.14 cubic inches/second.

Explanation:

R= 2in

S= π*R²= 12.56 inch²

rate= 0.25 in/sec

rate of soda sucked out= rate* S

rate of soda sucked out= 3.14 inch³/sec

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3 years ago

The light bulb converts electrical energy into light and ____. A) chemical B) electromagnetic C) heat D) nuclear

morpeh [17]

The light bulb converts electrical energy into light and heat.

Good luck! (:

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3 years ago

Read 2 more answers

Here, mA = 3.65 kg and mB = 7.05 kg. The string connecting the two objects is of negligible mass and the pulley is frictionless.

mr_godi [17]

Answer:

The magintude of the acceleration for both objects is $3.11m/s^2$

Explanation:

Drawing a free body diagram on the two boxes we can analyze the system more easily.

we can take the acceleration going up as positive for reference purposes.

for mA let's suppose that is ascending so:

$T_A-m_A*g=m_A*a$

and for mB (descending):

$T_B-m_B*g=-m_B*a$

$T_A=T_B$

because the two boxes has the same acceleration because they are attached together:

$m_B*g-m_B*a-m_a*g=m_a*a\\(m_B-m_A)*g=(m_a+m_B)*a\\a=\frac{(7.05kg-3.65kg)*9.8m/s^2}{3.65kg+7.05kg}\\\\a=3.11m/s^2$

So the magintude of the acceleration for both objects is $3.11m/s^2$

5 0

3 years ago

An electric bulb is rated 220 V and 100 W. When it is operated on 110 V, the

andrew-mc [135]

Answer:

50 W

Explanation:

Case 1

Power = V * I

100 = 220 * I

I = $\frac{100}{220}$ A

Case 2

P = V * I

P = 110 * $\frac{100}{220}$

P = 50 W

I think the answer is 50 W

Hope it helps

8 0

3 years ago

Which statement correctly compares sound and light waves ​

Which statement correctly compares sound and light waves