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Doss [256]
3 years ago
15

Which statement correctly compares sound and light waves ​

Physics
1 answer:
kolbaska11 [484]3 years ago
8 0

Answer:

Light waves carry energy parallel to the motion of the wave, while sound waves carry energy perpendicular to it. Sound waves carry energy parallel to the motion of the wave, while light waves carry energy perpendicular to it.

Explanation:

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Q/C An undersea earthquake or a landslide can produce an ocean wave of short duration carrying great energy, called a tsunami. W
iragen [17]

The amplitude A_{2} is 8.307 m

When describing the peak value of a quantity, such as the level of sound waves or the power and voltage in electrical and electronic systems, the term amplitude is employed. A louder sound has a bigger amplitude, and a softer sound has a smaller amplitude.

As we previously discussed in the concept session, the square root of the water's speed is inversely related to the amplitude of its waves.

A\alpha\frac{1}{\sqrt{v} }

Solve for first case:

A_{1}=\frac{1}{\sqrt{v_{1} } }

Solve for second case:

A_{2}=\frac{1}{\sqrt{v_{2} } }

So, the two equations is equal

A^{2} _{1}  v_{1} = A^{2} _{2} v_{2}

        =A^{2} _{2} \sqrt{g d_{2} }

Rearrange and solve for the amplitude A_{2} :

A_{2} =\sqrt{\frac{A^{2}_{1} v_{1} }{v_{2} } }

    =\sqrt{\frac{A^{2}_{1} v_{1}  }{\sqrt{g d_{2} } } }

    =\sqrt{\frac{(1.8m)^{2} X200 m/s }{\sqrt{9.8m/s^{2}X9 m } } }

    = 8.307 m

So, The amplitude A_{2} is 8.307 m.

Learn more about amplitude here:

brainly.com/question/3613222

#SPJ4

7 0
2 years ago
What is the drawback to use period of pendulum as time standard
Vadim26 [7]

The time period of a simple pendulum depends upon its length and value of'g'at any place. The period of the pendulum of fixed length

3 0
3 years ago
hot-air balloon is ascending at the rate of 14 m/s and is 84 m above the ground when a package is dropped over the side. (a) How
timurjin [86]

Answer:

a) t = 4.14 s

b) Speed with which it hits the ground = 40.58 m/s

Explanation:

Using the equations of motion,

g = 9.8 m/s², y = H = 84 m,

Initial velocity, u = 0 m/s,

final velocity, v = ?

Total Time of fall, t = ?

a) y = ut + gt²/2

84 = 0 + 9.8t²/2

4.9t² = 84

t² = 84/4.9

t = 4.14 s

b) v = u + gt

v = 0 + (9.8 × 4.14)

v = 40.58 m/s

4 0
3 years ago
Read 2 more answers
Volcanoes change the earth by
SOVA2 [1]
I believe the answer is b) slowly heating the surface
8 0
3 years ago
Read 2 more answers
Determine the magnitude of the current flowing through a 4.7 kilo ohms resistor if the voltage across it is (a) 1mV (b) 10 V (c)
mariarad [96]

Answer:

213 nA

2.13 mA

851e^-t μA

Explanation:

We have a pretty straightforward question here.

Ohms Law states that the current in an electric circuit is directly proportional to the voltage and inversely proportional to the resistance in the circuit. It is mathematically written as

V = IR, since we need I, we can write that

I = V/R

a) at V = 1 mV

I = (1 * 10^-3) / 4.7 * 10^3

I = 2.13 * 10^-7 A or 213 nA

b) at V = 10 V

I = 10 / 4.7 * 10^3

I = 0.00213 A or 2.13 mA

c) at V = 4e^-t

I = 4e^-t / 4.7 * 10^3

I = 0.000851e^-t A or 851e^-t μA

5 0
2 years ago
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