Answer:
Explanation:
<u>1) Equilibrium equation (given)</u>:
- H₂ (g) + I₂ (g) ⇄ 2HI (g)
<u>2) Equilibrium constant expression</u>:
<u>3) Determine the conentrations from the stoichiometry</u>:
a) <u>Number of moles</u>:
H₂ (g) + I₂ (g) ⇄ 2HI (g)
Start 0.4 1.55 0
Change - 0.4×0.6 = - 0.24 - 0.24 + 0.24×2 = + 0.48
--------------------------- ------------- --------------------------
End 0.16 1.31 0.48
b) <u>Concentrations</u>:
- [ H₂ (g) ] = 0.16 mole / 2 liter = 0.08 M
- [ I₂ (g) ] = 1.31 mole / 2 liter = 0.655 M
- [HI (g) ] = 0.48 mole / 2 liter = 0.24 M
<u>4) Compute Kc</u>:
- Kc = (0.24 M)² / (0.08 M × 0.655 M) = 1.099 ≈ 1.1 ← answer
Answer:
Explanation:
To convert from grams to moles we must use the molar mass, which is found on the Periodic Table.
Use the molar mass as a ratio.
Multiply by the given number of grams: 118
Flip the fraction so the grams of argon will cancel each other out.
The original measurement of grams had 3 significant figures, so our answer must have 3 sig figs.
For the number we calculated, that is the hundredth place. The 7 in the thousandth place tells us to round the 5 to a 6.
There are about <u>2.96 moles of Argon</u> in 118 grams.
Answer: C₇H₁₄ + 7O₂ → 7CO + 7H₂O
Explanation:
- For any equation to be balanced the number of (C, H, and O) atoms in the reactants side should be the same in the products side.
- The first choice is wrong because it is unbalanced equation that the reactants side has 22 O atoms and in the products side there is 14 O atoms.
- The second choice is wrong because the incomplete combustion of heptene results CO and/or CO₂ and H₂O.
- The third choice is the right answer that it has 7 atoms of C, 14 atoms of H, and 14 atoms of O in both reactants and products sides.
- The fourth choice is wrong because the combustion of heptene occurs in O₂ not in O.
Answer:
Here's what I get
Explanation:
1. Water
The O-H bond in water is highly polar.
It has about one-third ionic character.
The partially-positive H atoms and partially negative O atoms strongly attract each other by hydrogen bonds.
It takes a large amount of energy to separate the water molecules from each other.
Thus, the boiling point of water is relatively high (100 °C).
2. Acetone
The C=O bond in acetone is much less polar.
It is less than 20 % ionic.
The dipole-dipole attractions in acetone are much weaker than the hydrogen bonds in water.
It takes much less energy to separate the acetone molecules from each other.
Thus, even though the molar mass of acetone is more than three times that of water, the boiling point of acetone is only 56 °C.