1- the width of a rectangular box is twice the height and depth is 5 feet. if the volume is 160 ft 3, find the dimensions of the
box.
2- the perimeter of the rectangle room is 96 feet. If the length is 6 feet more than the width, find the dimensions of the room.
1 answer:
1. H=4
W=8
2. L=27
W=21
1. 160÷5=32
1/2 of 8 is 4
8×4=32
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2. 2×6=12
96-12=84
84÷4=21
21+6=27 (the length)
21= (the Width)
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