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2 years ago

13

when writing a repeating decimal as a fraction, why does the fraction always have only 9s or 9s and 0s as digits in the denomina

tor

1 answer:

Vaselesa [24]2 years ago

4 0

thats not necessarily true. 0.8333... is just 5/6 as a decimal. I suppose it depends on the number.

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50 points! Please help fast this is due soon and it confuses me. Will mark brainliest. Random answers will be reported. Please h

Ad libitum [116K]

Answer:(5,3)

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

it looks as though you made 72 of your goal so far for the month you only have 5 days left to reach 100% of your goal let me rem

dezoksy [38]

72% can also be written as 0.72, so take 0.72 x 45 = 32.4

Subtract 32.4 from 45 45 - 32.4 = 12.6 You need 12.6 renewals in 5 days.

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3 years ago

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How many solutions does the equation x_1 +x_2+x_3+x_4+x_5=21 have where x_1, x_2, x_3, x_4, and x_5 are nonnegative integers and

omeli [17]

Step-by-step explanation:

$x_{1} + x_{2} + x_{3} + x_{4} + x_{5} = 21\\$ (given)

Let us consider :

$x_{1}$ = $t_{1} + 1$

$x_{2}$ = $t_{2}$

$x_{3}$ = $t_{3}$

$x_{4}$ = $t_{4}$

$x_{5}$ = $t_{5}$

Now, by substituting the above considerations in the above equation, we get:

$t_{1} + 1 + t_{2} + t_{3} + t_{4} + t_{5} = 21\\$

$t_{1} + t_{2} + t_{3} + t_{4} + t_{5} = 20\\$

where,

$t_{i}$ $\geq$ 1

then it follows

n = 20

r = 4

then no. of solutions for the eqn = $_{r}^{n + r}\textrm{C}$

= $_{4}^{24}\textrm{C}$

= 10626

Answer :

no. of solutions for the eqn 10626

4 0

3 years ago

40 pounds of sugar are repackaged of 1/16 pounds each. how many packet of sugar are there?

jarptica [38.1K]

We know to each pound of such, there is 16 packets produced per?

So, 16 x 40 = 640.

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2 years ago

Pleaseeeee help I’m begging someone I PROMISE. I will mark brainlest

Lerok [7]

Answer:

Step-by-step explanation:

a) x>0 → items can not be negative

b) c(2,000) = 5,000+1.3(2,000) = $7,600

c)5,000+1.3x<10,000

5,000-5,000+1.3x<10,000-5,000

1.3x<5,000

x<3846 items

5 0

3 years ago