Question

In 1977 off the coast of Australia, the fastest speed by a vessel on the water

Answer 1

Answer: 154.08 m/s

Explanation:

Average acceleration $a_{ave}$ is the variation of velocity  $\Delta V$ over a specified period of time  $\Delta t$:

$a_{ave}=\frac{\Delta V}{\Delta t}}$

Where:

$a_{ave}=1.80 m/s^{2}$

$\Delta V=V_{f}-V_{o}$ being $V_{o}=0$ the initial velocity and $V_{f}$ the final velocity

$\Delta t=85.6 s$

Then:

$a_{ave}=\frac{V_{f}-V_{o}}{\Delta t}}$

Since $V_{o}=0$:

$a_{ave}=\frac{V_{f}}{\Delta t}}$

Finding $V_{f}$:

$V_{f}=a_{ave} \Delta t$

$V_{f}=(1.80 m/s^{2})(85.6 s)$

Finally:

$V_{f}=154.08 m/s$