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3 years ago

What would happen if this cell were moved from pure water to a seawater solution?

1 answer:

3 0

The cell would swell and burst, because the 20% salt solution is hypotonic with respect to the cell, causing a net movement of water into the cell. Example, water moves from the blood filtrate that will form urine. The same will do while pure water moved to seawater.

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Simón Bolívar and José de San Martín are figures associated with what event?

Jobisdone [24]

The event is South American independence. Option D.

By 1820, royalist Peru was an isolated outpost of Spanish influence. San Martin liberated Chile and Argentina to the south while Simon Bolivar and Antonio Jose de Sucre liberated Ecuador Colombia, and Venezuela to the north leaving only Peru and present-day Bolivia under Spanish control.

Simon Bolivar wrote two of his political treatises. The Manifesto de Cartagena Declaration of Cartagena and Carta de Jamaica Letters from Jamaica told the people of South America that Spain urged them to rebel against their colonial rule. Simon Bolivar is a Creole who grew up in a wealthy family. Bolivar devoted his time and effort to fight for Venezuela's independence from Spain. Bolivar was inspired by the Enlightenment ideas of John Locke.

Learn more about Simon Bolivar here:-brainly.com/question/1402690

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11 months ago

What occurs when a gas is changed into a liquid

ankoles [38]

for liquid to gas, Evaporation or vaporization.

for gas to liquid, condensation occurs. The opposite of evaporation. Condensation is when the gas gives up it's latent heat and simply condenses.

7 0

3 years ago

What is the molar mass of copper(II)nitrate

andriy [413]

187.56 g/mol
That is the answer

8 0

3 years ago

Read 2 more answers

Which is an example of making a quantitative observation?

lions [1.4K]

Measuring the surface of an oil painting and finding its dimensions 12 to be 12 inches

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2 years ago

Calculate the freezing point (in degrees C) of a solution made by dissolving 7.99 g of anthracene{C14H10} in 79 g of benzene. Th

mario62 [17]

Answer: The freezing point of solution is 2.6°C

Explanation:

To calculate the depression in freezing point, we use the equation:

$\Delta T_f=iK_fm$

Or,

$\Delta T_f=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}$

where,

$\Delta T_f$ = $\text{Freezing point of pure solution}-\text{Freezing point of solution}$

Freezing point of pure solution = 5.5°C

i = Vant hoff factor = 1 (For non-electrolytes)

$K_f$ = molal freezing point depression constant = 5.12 K/m = 5.12 °C/m

$m_{solute}$ = Given mass of solute (anthracene) = 7.99 g

$M_{solute}$ = Molar mass of solute (anthracene) = 178.23 g/mol

$W_{solvent}$ = Mass of solvent (benzene) = 79 g

Putting values in above equation, we get:

$5.5-\text{Freezing point of solution}=1\times 5.12^oC/m\times \frac{7.99\times 1000}{178.23g/mol\times 79}\\\\\text{Freezing point of solution}=2.6^oC$

Hence, the freezing point of solution is 2.6°C

8 0

2 years ago