Answer:
the angular acceleration of the car is 1.5 rad/s²
Explanation:
Given;
initial angular velocity, = 10 rad/s
final angular velocity, = 25 rad/s
time of motion, t = 10 s
The angular acceleration of the car is calculated as follows;
Therefore, the angular acceleration of the car is 1.5 rad/s²
Complete Question
The complete question is shown on the first and second uploaded image
Answer:
a
Now the ratio of the gases in Gabor's lungs at the depth of 15m to that at
the surface is
b
The number of moles of gas that must be released is
Explanation:
We are told from the question that the pressure at the surface is 1 atm and for each depth of 10m below the surface the pressure increase by 1 atm
This means that the pressure at the depth of the surface would be
The ideal gas equation is mathematically represented as
Where P is pressure at the surface
V is the volume
R is the gas constant = 8.314 J/mol. K
making n the subject we have
Considering at the surface of the water the number of moles at the surface would be
Substituting for
,
for volume , 8.314 J/mol. K for R , (37° +273) K for T into the equation
To obtain the number of moles at the depth of the water we use
Where are pressure and no of moles at the depth of the water
Substituting values we have
Now to obtain the number of moles released we have
The molar concentration at the surface of water is
The molar concentration at the depth of water is
Now the ratio of the gases in Gabor's lungs at the depth of 15m to that at the surface is
