Answer:
What is the membrane's conductance = 2.47miuS
Explanation:
The detailed step and appropriate formula is as shown in the attached file.
F = ma
200 = 50 * a
4 = a
Therefore acceleration is 4ms^-2
Acceleration= velocity/time
1.1/2.7=0.41
The acceleration is .41 m/s^2
B-allow electrons to flow
Answer:
The 40g mass will be attached at 69 cm
Explanation:
First, make a sketch of the meterstick with the masses placed on it;
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↓ Δ ↓
20 g.................50 cm.................40g
38 cm y cm
Apply principle of moment;
sum of clockwise moment = sum of anticlockwise moment
40y = 20 (38)
40y = 760
y = 760 / 40
y = 19 cm
Therefore, the 40g mass will be attached at 50cm + 19cm = 69 cm
12cm 50 cm 69cm
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↓ Δ ↓
20 g.................50 cm.................40g
38 cm 19 cm
