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astraxan [27]
3 years ago
12

Blocks with masses of 3.0 kg, 4.0 kg, and 5.0 kg are lined up in a row on a frictionless table. All three are pushed forward by

a 16 N force applied to the 3.0 kg block. How much force does the 4.0 kg block exert on the 5.0 kg block?
Physics
1 answer:
exis [7]3 years ago
5 0

Answer:

This is very hard bit I think 6.3 my, I'm not shure.

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Answer:

The induced emf  is  \epsilon  = 0.1041 \  V  

Explanation:

From the question we are told that

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substituting values

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substituting values

       A =  3.142 *   (0.095)^2

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The angular velocity is mathematically represented as

        w =  2 *  \pi  *  \frac{c}{\lambda }

substituting values          

       w =  2 *  3.142   *  \frac{3.0*10^{8}}{ 6.90 }  

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Generally the induced emf is mathematically represented as

        \epsilon  =  N *  B  *  A  *  w * sin (wt )

At maximum induced emf  sin (wt)  =  1

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         \epsilon  =  N *  B  *  A  *  w

substituting values

         \epsilon  = 1  *    1.342 *10^{-8}   *  0.0284  *2.732 *10^{8}  

         \epsilon  = 0.1041 \  V  

         

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