The rider's horizontal motion, and how much ground he covers before he hits it, have nothing to do with how long he takes to hit the ground. The problem is simply: "How long does it take an object to fall 1.12 m from rest ?"
This seems like a good time to use this formula:
Distance fallen from rest = (1/2) (acceleration) (time)²
The problem doesn't tell us what planet the skateboarder is exercising on. I'm going to assume it's on Earth, where the acceleration of gravity is 9.8 m/s². And now, here's the solution to the problem I just invented:
1.12 m = (1/2) (9.8 m/s²) (time)²
Time² = (1.12 m) / (9.8 m/s²)
Time² = 0.1143 sec²
Time = √(0.1143 sec² )
<em>Time = 0.34 second</em>
Answer:
= 729 Joules
Explanation:
Heat absorbed by a substance is given by the formula;
Q = m×c×ΔT
Where; Q is the heat absorbed
m is the mass of the substance
ΔT is the change in temperature;
The specific heat capacity of iron is 450 J/Kg/K
Therefore;
Heat absorbed = 0.06 kg × 27 × 450
= 729 Joules
The magnetic field strength at point 1 in the figure will be 6.67 ×10⁻⁵ T.
<h3>What is magnetic field strength?</h3>
The number of magnetic flux lines on a unit area passing perpendicular to the given line direction is known as induced magnetic field strength .it is denoted by B.
The magnetic field strength is found as;
![B = \frac{\mu_0I}{2r} \\\\ \mu_0 = 4 \PI \times 10^{-7}](https://tex.z-dn.net/?f=B%20%3D%20%5Cfrac%7B%5Cmu_0I%7D%7B2r%7D%20%20%5C%5C%5C%5C%20%5Cmu_0%20%3D%204%20%5CPI%20%5Ctimes%2010%5E%7B-7%7D)
In the formula,I denote current, and r denotes the distance between the point and the current carrying wire and magnetic field due to current in the bottom wire.
At point 1, the net magnetic field is found as the sum of magnetic field due to current in the top wire.
![\rm B_{net} = B1_+(-B_2)](https://tex.z-dn.net/?f=%5Crm%20B_%7Bnet%7D%20%3D%20B1_%2B%28-B_2%29)
![B = \frac{ 4 \PI \times 10^{-7}I}{2r} \\\\ \rm B_{net} = B_1_+(-B_2)\\\\ \rm B_{net} = \frac{4 \times \pi \times 10^{-7} \times 10}{2 \times \pi \times 0.02} -\frac{4 \times \pi \times 10^{-7} \times 10 }{2 \times \pi \times 0.06} \\\\\ \rm B_{net} = 6.67 \times 10^{-5} T](https://tex.z-dn.net/?f=B%20%3D%20%5Cfrac%7B%204%20%5CPI%20%5Ctimes%2010%5E%7B-7%7DI%7D%7B2r%7D%20%20%5C%5C%5C%5C%20%20%5Crm%20B_%7Bnet%7D%20%3D%20B_1_%2B%28-B_2%29%5C%5C%5C%5C%20%5Crm%20B_%7Bnet%7D%20%3D%20%5Cfrac%7B4%20%5Ctimes%20%5Cpi%20%5Ctimes%2010%5E%7B-7%7D%20%5Ctimes%2010%7D%7B2%20%5Ctimes%20%5Cpi%20%5Ctimes%200.02%7D%20-%5Cfrac%7B4%20%5Ctimes%20%5Cpi%20%5Ctimes%2010%5E%7B-7%7D%20%5Ctimes%2010%20%7D%7B2%20%5Ctimes%20%5Cpi%20%5Ctimes%200.06%7D%20%5C%5C%5C%5C%5C%20%20%5Crm%20B_%7Bnet%7D%20%3D%206.67%20%5Ctimes%2010%5E%7B-5%7D%20T)
Hence, the magnetic field strength at point 1 in the figure will be 6.67 ×10⁻⁵ T.
To learn more about the strength of induced magnetic field, refer:
brainly.com/question/2248956
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