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Finger [1]
2 years ago
15

What are the intermolecular forces present in acetone?

Chemistry
1 answer:
notka56 [123]2 years ago
3 0

Answer:

dipole-dipole interactions.

Explanation:

hope this helps

plz mark brainliest

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g Green plants use light from the Sun to drive photosynthesis. Photosynthesis is a chemical reaction in which water and carbon d
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Answer:

6.49g

Explanation:

Let's consider the balanced reaction for photosynthesis.

6 CO₂ + 6 H₂O = C₆H₁₂O₆ + 6 O₂

We can establish the following relations:

  • 1 mole of CO₂ has a mass of 44.01 g (MW 44.01)
  • The molar ratio of CO₂ to C₆H₁₂O₆ is 6:1.
  • 1 mole of C₆H₁₂O₆ has a mass of 180.16 g/mol.

The mass of glucose produced by the reaction of 9.51 g of carbon dioxide is:

9.51gCO_2 \times \frac{1molCO_2}{44.01gCO_2}  \times \frac{1molGlucose}{6molCO_2}  \times \frac{180.16gGlucose}{1molGlucose} = 6.49g Glucose

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How do you dilute a concentrated solution?
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add more water

Explanation:

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When two metals touch in the mouth, a small shock is created. this is known as<br> a?
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 <span>When two metals touch in the mouth, a small shock is created. this is known as a </span>galvanic action
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Scientists made the following two observations about emission spectra: each element has a unique emission spectrum. atoms emit e
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Ammonia is produced by the following reaction. 3H2(g) N2(g) Right arrow. 2NH3(g) When 7. 00 g of hydrogen react with 70. 0 g of
harkovskaia [24]

In the ammonia production process given by the reaction 3H₂(g) + N₂(g) → 2NH₃(g), when 7.00 g of hydrogen react with 70.0 g of nitrogen, hydrogen is considered the limiting reactant because <u>7.5 moles of hydrogen would be needed to consume the available nitrogen</u> (option 1).

The reaction is the following:

3H₂(g) + N₂(g) → 2NH₃(g)   (1)

To know why hydrogen is considered the limiting reactant, we need to calculate the number of moles of nitrogen and hydrogen with the following equation:

n = \frac{m}{M}

Where:    

m: is the mass

M: is the molar mass

  • For <em>hydrogen </em>we have:

n_{H_{2}} = \frac{m}{M} = \frac{7.00 g}{2.016 g/mol} = 3.47 \:moles

  • And for <em>nitrogen</em>:

n_{N_{2}} = \frac{m}{M} = \frac{70.0 g}{28.013 g/mol} = 2.50 \:moles

We can see in reaction (1) that <u>3 moles of hydrogen</u> react with <u>1 mol of nitrogen</u>, so the number of hydrogen moles needed to react nitrogen is:

n_{H_{2}} = \frac{3\:moles\:H_{2}}{1\:moles\:N_{2}}*n_{N_{2}} = \frac{3\:moles\:H_{2}}{1\:moles\:N_{2}}*2.50 \:moles = 7.50 \:moles

Since we have <u>3.47 moles of hydrogen</u> and we need <u>7.50 moles</u> to react with all the mass of nitrogen, the <em>limiting reactant</em> is <em>hydrogen</em>.

We can find the number of ammonia moles produced with the limiting reactant (hydrogen) konwing that <u>3 moles of hydrogen</u> produces <u>2 moles of ammonia</u>, so:

n_{NH_{3}} = \frac{2\:moles\:NH_{3}}{3\:moles\:H_{2}}*n_{H_{2}} = \frac{2\:moles\:NH_{3}}{3\:moles\:H_{2}}*3.47 \:moles = 2.31 \:moles

Hence, hydrogen would produce <u>2.31 moles of ammonia</u>.

Therefore, hydrogen is the limiting reactant because <u>7.5 moles of hydrogen would be needed to consume the available nitrogen</u> (option 1).

Find more about limiting reactants here:

brainly.com/question/2948214?referrer=searchResults

   

I hope it helps you!                        

6 0
2 years ago
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