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djverab [1.8K]
3 years ago
11

When driving during the daytime in reduced visibility, such as rain, smoke, or fog,

Engineering
1 answer:
riadik2000 [5.3K]3 years ago
3 0

Answer:A

Explanation:

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Stephen Covey believes this principle is the key to effective interpersonal communication. Seek first to understand, then to be understood. This habit is about communicating with others. It's about developing the habit of listening carefully and really understanding the other person BEFORE giving your thoughts.

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What branch of chemistry is credited with the development of silicone?
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C). Inorganic Chemistry

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Wiring harnesses run
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4 years ago
Based on experimental observations, the acceleration of a particle is defined by the relation a = –(0.1 + sin x/b), where a and
Allisa [31]

Answer:

a) v = +/- 0.515 m/s

b) x = -0.098164 m

c)  v = +/- 1.005 m/s

Explanation:

Given:

The relationship for the acceleration is given as follows:

                            a = - (0.1 + sin(x/b))

Where,  b = 0.98

- IVP is v = 1 m/s @ x = 0

Find:

(a) the velocity of the particle when x = -1 m

(b) the position where the velocity is maximum

(c) the maximum velocity.

Solution:

- We will compute the velocity by integrating a by dt.

                          a = v*dv / dx =  - (0.1 + sin(x/0.98))

- Separate variables:

                          v*dv = - (0.1 + sin(x/0.98)) . dx

-Integrate from v = 1 m/s to v and @ x = 0 to x:

                         0.5*(v^2) = - (0.1*x - 0.98*cos(x/0.8)) - 0.98 + 0.5

                         0.5*v^2 =  0.98*cos(x/0.98) - 0.1*x - 0.48

- Evaluate at, x = -1

                         0.5*v^2 = 0.98 cos(-1/0.98) + 0.1 -0.48

                         v = sqrt (0.2651155)

                         v = +/- 0.515 m/s

- v = v_max when a = 0. Set the given expression to zero and solve for x:

                          -0.1 = sin(x/0.98)

                           x = -0.98*0.1002

                           x = -0.098164 m

- Hence now evaluate velocity through the derived expression:

                           v^2 = 1.96 cos(-0.098164/0.98) -0.96 -0.2*-0.098164

                           v = sqrt (1.0098)

                           v = +/- 1.005 m/s

4 0
3 years ago
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