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Alenkasestr [34]
3 years ago
13

What instrument measures the flow rate of a liquid by comparing the flow through two sections of tapered pipe?

Chemistry
1 answer:
Alexeev081 [22]3 years ago
5 0
Turbine flow meter is the answere
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Someone please help me and answer my question asap. i need to turn my assignment in soon... please.
Ksenya-84 [330]

Answer:

Explanation:

a. the salt produced would be Mg3N2(magnesium nitride)

b. magnesium loses 2 electron to form Mg2+ ion and nitrogen gains 3 electron to form n3-

when several of these ions come together 3 Mg2+ ion combine with 2 n3- ion to form Mg3N2 thus Mg getting six electron from nitrogen to form a ionic bond.

c. the reaction is not balanced Mg + N2 = Mg3n2

to make it balanced the reaction should be 3 Mg + N2 = Mg3N2.

the reaction was not balanced before because the number of Mg on both side of the reaction was not equal.

d. magnesium nitrate has formula Mg(NO3)2 is formed when Mg combines with nitrogen and oxygen Mg + N2 + o2

8 0
3 years ago
What would happen if the amount of chlorofluorocarbons would suddenly increase and what would happen to the climate?
mario62 [17]
If CFC increases, there will be a ozone depletion ! the UV rays starts entering and leads to mutation and deaths !

the temperature of the climate increases drastically !
4 0
3 years ago
Roxanne was asked by her teacher to explain why sodium ions (Na) and chlorine ions (CI) combine into sodium chloride (NaCl).
DedPeter [7]

Answer:

Roxanne said it was because chlorine is highly electronegative and sodium has a low ionization energy and that the ions Na and cr both have full electron shells.

3 0
3 years ago
iodide-131 decays with half life of 8.02 d. In a Sample initially containing 5.00 mg of I 131, what mass remains after 6.01 d?
Genrish500 [490]
You can use the equation f(t) = 5*(1/2)^(t/8.02)

Then plug in 6.01 for time.There remains 2.97 mg in the sample.

5 0
3 years ago
What is the only additional information needed to calculate the empirical formula of a compound if the masses of each element of
Natasha_Volkova [10]

Mass percentages of the the elements in the compound is the only additional information needed to calculate the empirical formula of a compound if the masses of each element of the compound are provided.

<h3>What is Empirical Formula ? </h3>

The Empirical formula is the simplest whole number ratio of atoms present in given compound.

<h3>What is Molecular formula of Compound ?</h3>

Molecular Formula = Empirical Formula × n

n =  \frac{\text{Molar Mass}}{\text{Empirical Formula weight}}

Thus from the above conclusion we can say that Mass percentages of the the elements in the compound is the only additional information needed to calculate the empirical formula of a compound if the masses of each element of the compound are provided.

Learn more about Empirical Formula here: brainly.com/question/1603500

#SPJ4

5 0
2 years ago
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