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Anestetic [448]
3 years ago
7

A hydrocarbon of pentane has two isomeric forms—n-pentane and iso-pentane. The molecular formula of the n-pentane is C5H12. Pred

ict the molecular formula of the iso-pentane.
Chemistry
1 answer:
Monica [59]3 years ago
5 0
An iso pentane is an isomeric form of n-pentane. Isomers have same molecular formula but differ in the atomic arragement projected in 3D and the arrangement of atoms primarily resulting to a different set of properties. In this case, isopentane also has a molecular formula of an alkane <span>C5H12</span>
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Write the full ground state electron configuration of f+.
ANTONII [103]

Answer:- 1s^22s^22p^4 .

Explanation:- Atomic number for fluorine(F) is 9 and it's electron configuration is 1s^22s^22p^5 . F^+ is formed when F loses one electron from it's valence shell.

F\rightarrow F^++1e^-

Second shell is the valence shell for fluorine and so it loses one electron from 2p to form  F^+  and the electron configuration of the ion becomes 1s^22s^22p^4 .


7 0
3 years ago
4Fe +302 + 2Fe2O3 <br> How many grams of Fe2O3 will be produced from 10.0 g of Fe and 7.00 g of O2?
Molodets [167]

Answer:10g of Fe produces 14.37g of Fe2O3

7g of O2 produce 46.84g of Fe2O3

Explanation:

3 0
3 years ago
Part a use these data to calculate the heat of hydrogenation of buta-1,3-diene to butane. c4h6(g)+2h2(g)→c4h10(g)
Reptile [31]

<u>Answer:</u> The heat of hydrogenation of the reaction is coming out to be 234.2 kJ.

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as \Delta H

The equation used to calculate enthalpy change is of a reaction is:

\Delta H_{rxn}=\sum [n\times \Delta H_{(product)}]-\sum [n\times \Delta H_{(reactant)}]

For the given chemical reaction:

C_4H_6(g)+2H_2(g)\rightarrow C_4H_{10}(g)

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(1\times \Delta H_{(C_4H_{10})})]-[(1\times \Delta H_{(C_4H_6)})+(2\times \Delta H_{(H_2)})]

We are given:

\Delta H_{(C_4H_{10})}=-2877.6kJ/mol\\\Delta H_{(C_4H_6)}=-2540.2kJ/mol\\\Delta H_{(H_2)}=-285.8kJ/mol

Putting values in above equation, we get:

\Delta H_{rxn}=[(1\times (-2877.6))]-[(1\times (-2540.2))+(2\times (-285.8))]\\\\\Delta H_{rxn}=234.2J

Hence, the heat of hydrogenation of the reaction is coming out to be 234.2 kJ.

4 0
3 years ago
Which of the following is a correct description of a double bond between two carbon atoms
kicyunya [14]

A double bond between carbon atoms is longer than a triple bond between carbon atoms.

5 0
3 years ago
What is the percentage of oxygen in Li(NO2)3
BartSMP [9]

Answer:

66.2 % of O

Explanation:

Our compound is the lithium nitrite.

LiNO₂

This salt is ionic and can be dissociated: LiNO₂ →  Li⁺ + NO₂⁻

We determine the molar mass:

molar mass of Li + 3 . molar mass of N + 6 . molar mass of O

6.94 g/mol + 3. 14 g/mol + 6 . 16 g/mol = 144.94 g/mol

The mass of oxygen contained in 1 mol of lithium nitrite is:

6 . 16 g/mol = 96 g

So the percentage of oxygen present is:

(96 g / 144.94 g) . 100 = 66.2 %

3 0
3 years ago
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