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sesenic [268]
3 years ago
12

a 0.4 kg block rests on a desk. the coefficient of static friction is 0.2. You push the side of the block but do not have a spri

ng scale to measure the force you use. the block does not move. which statement is true about the force of static friction?
Physics
2 answers:
ladessa [460]3 years ago
7 0
Static friction is greater than Applied force
saw5 [17]3 years ago
6 0

Answer:

D. It is no smaller than 0.78N

Explanation:

The question is incomplete. These are all the options :

A. It is no larger than 0.78N

B. It is 0.78N

C. It is 0.08N

D. It is no smaller than 0.78N

To solve this problem, we have the data of :

m=0.4kg

Where ''m'' is the mass of the block

μ = 0.2

Where ''μ'' is the coefficient of static friction

If we want to find the magnitude of the force of static friction we need to use the following equation :

F_{sf}= μ.F_{N} (I)

Where ''F_{N}'' is the normal force that the desk exerts on the block. Its magnitude is equal to the weight (because we suppose that the block rests horizontally on the desk).

The weight ''W'' can be calculated as :

W=m.g

Where ''m'' is the mass and ''g'' is the acceleration due to gravity.

The value of ''g'' is

g=9.81\frac{m}{s^{2}}

The weight of the block is

W=(0.4kg).(9.81\frac{m}{s^{2}})

W=3.924N

Now, the weight is equal to the normal force ⇒

W=F_{N}=3.924N

Using the equation (I) :

F_{sf}=(0.2).(3.924N)

F_{sf}=0.7848N

The correct option is D. It is no smaller than 0.78N

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