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OlgaM077 [116]
3 years ago
15

The total weight of a car with passengers is 30,000N. The area of contact of each of the four tyres with the ground is 0.025m2.

Determine the minimum car tyre pressure
Physics
1 answer:
vlabodo [156]3 years ago
7 0

Answer:

<em>The minimum pressure car tire pressure is 300,000 Pa</em>

Explanation:

<u>Pressure</u>

It's a measure of the force exerted by an object per unit surface:

\displaystyle P=\frac{F}{A}

Where F is the force applied on a surface area A.

We are given the total weight of a car with passengers as Ft=30,000 N and we also know the area of contact of each tire with the ground as A=0.025 m^2.

The minimum pressure each tire can have is when the total weight is evenly distributed in all four tires, thus F=Ft/4=7,500 N.

Calculating the pressure:

\displaystyle P=\frac{7,500}{0.025}

P=300,000 Pa

The minimum pressure car tire pressure is 300,000 Pa

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A car is running at a velocity of 50 miles/hour and the driver accelerates the car by 10miles/hour.How far the car travels from
dezoksy [38]
Initial velocity u = 50 miles/hour
acceleration a = 10 miles/hour
Time t = 2 hours
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Substituting the values in the second equation of motion,
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S = 120 miles
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A 1.60 m tall person lifts a 2.10-kg book from the ground so it is 2.20 m above the ground. What is the potential energy of the
Viefleur [7K]

Answer:

Explanation:

Given

mass of book(m)=2.1 kg

height up to which book is lifted is (h)2.2 m

height of person (h_0)1.6 m

Potential energy of book relative to ground=mgh

PE=2.1\times 9.8\times 2.2=45.276 J

(b)PE w.r.t to person head =mg(h-h0)

=2.1\times 9.8\times (2.2-1.6)=12.348 J

work done by person in lifting box 2.2 m w.r.t floor

Word done =Potential Energy of box relative to floor=45.2 J

6 0
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A marble rolls along the floor with a constant velocity of 6 m/s. How far will it have gone after 130 seconds
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Answer:

0.046

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A curve of radius 53.1 m is banked so that a car of mass 2.9 Mg traveling with uniform speed 67 km/hr can round the curve withou
prisoha [69]

Answer:

33.65°

Explanation:

radius, r = 53.1 m

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convert km/h into m/s

v = 18.61 m/s

Let the angle of banking of road is θ, without friction

tan\theta =\frac{v^{2}}{rg}

tan\theta =\frac{18.61^{2}}{53.1\times 9.8}

tan  θ = 0.6655

θ = 33.65°

Thus, the angle of banking of road is 33.65°.

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