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Drupady [299]
2 years ago
5

State the term used to describe the turning force exerted by the man

Physics
1 answer:
ozzi2 years ago
8 0

]A force called the effort force is applied at one point on the lever in order to move an object, known as the resistance force, located at some other point on the lever.

The way levers work is by multiplying the effort exerted by the user. Specifically, to lift and balance an object, the effort force the user applies multiplied by its distance to the fulcrum must equal the load force multiplied by its distance to the fulcrum. Consequently, the greater the distance between the effort force and the fulcrum, the heavier a load can be lifted with the same effort force.

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Is there ever a situation where an ant will have more momentum than an elephant? Explain why or why not? Question 2 options: Yes
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An ant can have more momentum than an elephant when the elephant is standing still.

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Imagine that a space probe could be fired as a projectile from the Earth's surface with an initial speed of 5.52 104 m/s relativ
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Answer:

v_f = 5.4 \times 10^4 m/s

Explanation:

As per energy conservation we can say

initial total energy of the object at the surface of earth = final total energy of the object at highest height

now we have

U_i = -\frac{GMm}{R} + \frac{1}{2}mv^2

here we know that

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m = mass of object

R = radius of earth

now when object reached far away from the earth then it will only have kinetic energy

U_f = \frac{1}{2}mv_f^2

now by energy conservation

-\frac{GMm}{R} + \frac{1}{2}mv^2 = = \frac{1}{2}mv_f^2

-\frac{GM}{R} + \frac{1}{2}v^2 = \frac{1}{2}v_f^2

-\frac{(6.67 \times 10^{-11})(5.98\times 10^{24})}{6.37\times 10^6} + \frac{1}{2}(5.52 \times 10^4)^2 = \frac{1}{2}v_f^2

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v_f = 5.4 \times 10^4 m/s

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3 years ago
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