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ohaa [14]
3 years ago
7

The period of a sound 440-Hertz sound wave is how many second/second.

Chemistry
1 answer:
masha68 [24]3 years ago
3 0
440 hertz = 440/seconds
1/440 seconds = period of the sound wave.
so Answer is 2.2727272* 10^-3 second or 1/440 seconds
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An unknown piece of metal weighing 95.0 g is heated to 98.0°C. It is dropped into 250.0 g of water at 23.0°C. When equilibrium i
lutik1710 [3]

Answer:

C_{metal}=126.6\frac{J}{g\°C}

Explanation:

Hello!

In this case, when two substances at different temperature are put in contact and an equilibrium temperature is attained, we can evidence that the heat lost by the hot substance (metal) is gained by the cold substance (water) and we can write:

Q_{metal}=-Q_{water}

Which can be also written as:

m_{metal}C_{metal}(T_{EQ}-T_{metal})=-m_{water}C_{water}(T_{EQ}-T_{water})

Thus, since we need the specific heat of the metal, we solve for it as shown below:

C_{metal}=\frac{m_{water}C_{water}(T_{EQ}-T_{water})}{-m_{metal}(T_{EQ}-T_{metal})} \\\\C_{metal}=\frac{250.0g*4.184\frac{J}{g\°C}(29.0\°C-98.0\°C)}{95.0g(29.0\°C-23.0\°C)} \\\\C_{metal}=126.6\frac{J}{g\°C}

Best regards.

7 0
2 years ago
Determine the mass in grams of sucrose that must be added to 26 g of water to make a 1.15 m solution. Enter your answer to 2 dec
True [87]

Answer:

10.23 grams of sucrose should be added.

Explanation:

1.15 m means molality (moles of solute in 1kg of solvent)

1.15 moles of sucrose are contained in 1 kg of solvent (1000 g)

Let's determine the moles in our mass of solvent.

Firstly we convert the g to kg → 26 g . 1kg/1000g = 0.026 kg

m . mass (kg) =  1.15 mol/kg . 0.026kg → 0.0299 moles.

Finally we convert the moles to mass (mol . molar mass)

0.0299 mol . 342.3 g/mol = 10.23 g

4 0
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Answer:

Kb =  7.1 x 10⁻¹³

Explanation:

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