In a circle of diameter 30 cm a chord of 10cm is drawn. To 2 decimal places, how far is the chord from the center of the circle?
1 answer:
<u>Given:</u>
The circle has a diameter of 30 cm and a chord of 10 cm is drawn.
Radius of the circle = 15 cm
Half of the chord = 5 cm
We need to determine the distance of chord from the center of the circle.
<u>Distance of chord from the center of the circle:</u>
Let us use the Pythagorean theorem, to find the distance between the center and the chord.
Let d denote the distance between the center and the chord of the circle.
Thus, we get;
Taking square root on both sides, we get;
Thus, the distance between the center and the chord of the circle is 14.14 cm.
Hence, Option A is the correct answer.
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Answer:
Step-by-step explanation:
as given j=h and k=m then which expression for g is
as from attached image , we can see that its look like two right angle triangle
so from lower triangle we apply the pythagorean theorem .
which state that sum of the squares on the legs of a right triangle is equal to the square on the hypotenuse.
so small triangle ΔEBD
h² +k²= g² ---------------(1)
now from big triangle ΔABC
(j + h)² +(m + h)² =f²---------(2)
given j=h and k=m so from equation-2 we can find ,
(h + h)² +(k+ k)² =f²
(2h)² +(2k)²=f²
4h²+ 4k²= f²
4(h²+k²)= f² ----------(3)
now from equation 1 and 3 we can obtained .
4×g² =f²
take square root both side we get,
2×g=f
so g=f/2----- Answer
