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3 years ago

Choose all the answers that apply. What are examples of how science has influenced technology?

Chemistry

2 answers:

Fudgin [204]3 years ago

5 0

Answer:

A and B

Explanation:

A: The discovery of x- rays is a scientific discovery that led to X-ray machines which is technology.

B: Finding out that massive amounts of energy can be released by splitting the nucleus of an atom was the discovery and it led to nuclear power plants.

Satellites helping scientists map the earth doesn't really have an example of science. It just says that Satellites help scientists, and satellites are technology.

Robotic machines are also technology. Robots assisting doctors in surgery is technology helping people not science influencing technology.

So A and B would be the answers.

Hope this helps :)

madreJ [45]3 years ago

4 0

Answer:

b,c,e,f

Explanation:

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Triglycerides, fatty acids and glycerol differ with respect to polarity, H-bonds, and functional groups. Discuss the differences

Black_prince [1.1K]

Answer:

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Explanation:

Triglycerides are made when 3 molecules of fatty acids condenses with one molecule of glycerol having 3-sites of OH where the condensation takes place with the COOH functional group in the fatty acids and 3 molecules of water

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3 years ago

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saveliy_v [14]

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2 years ago

Help me with these questions :)

maxonik [38]

Answer:

1 ) H2O 2) Hydrogen and oxygen 3) Compound

Explanation:

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3 years ago

When might a large volume of material have little mass

Natali5045456 [20]

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2 years ago

When adjusted for any changes in ΔHΔH and ΔSΔS with temperature, the standard free energy change ΔG∘TΔGT∘Delta G_{T}^{\circ} at

STALIN [3.7K]

The equilibrium constant is 0.0022.

Explanation:

The values given in the problem is

ΔG° = 1.22 ×10⁵ J/mol

T = 2400 K.

R = 8.314 J mol⁻¹ K⁻¹

The Gibbs free energy should be minimum for a spontaneous reaction and equilibrium state of any reaction is spontaneous reaction. So on simplification, the thermodynamic properties of the equilibrium constant can be obtained as related to Gibbs free energy change at constant temperature.

The relation between Gibbs free energy change with equilibrium constant is ΔG° = -RT ln K

So, here K is the equilibrium constant. Now, substitute all the given values in the corresponding parameters of the above equation.

We get,

$1.22 * 10^{5} = - 8.314* 2400 * ln K$

$\\ 1.22 * 10^{5} = -19953.6 * ln K$

$ln K = \frac{-1.22*10^{5} }{19953.6} =-6.114\\\\k =e^{-6.114}=0.0022$

So, the equilibrium constant is 0.0022.

4 0

2 years ago