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Vinvika [58]
4 years ago
5

RES

Chemistry
2 answers:
lubasha [3.4K]4 years ago
6 0

Answer: A, C, E

Explanation:

Got it right

satela [25.4K]4 years ago
3 0

Answer:

A C E

Explanation:

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A copper atom has a mass of 1 06 times 10^-22 g and a penny has a mass of 2.5 g. Use this information to answer the questions be
amm1812

Answer:

Mass of 1 mole of copper is 63.83 g.

0.03916 moles of copper atoms have a mass equal to the 2.5 grams of copper penny.

Explanation:

Mass of 1 copper atom,m = 1.06\times 10^{-22} g

1 mole = 6.022\times 10^{23} atoms

Mass of 1 mole of copper :

= 6.022\times 10^{23} atoms\times 1.06\times 10^{-22} g=63.83 g

Mass of 1 mole of copper = 63.83 g

Mass of copper penny = 2.5 g

Atomic mass of copper = 63.83 g/mol

Moles of copper in 2.5 g of copper penny:

\frac{2.5 g}{63.83 g/mol}=0.03916 mol

0.03916 moles of copper atoms have a mass equal to the 2.5 grams of copper penny.

8 0
3 years ago
14 protons,14 electrons and 14 neutrons
vovikov84 [41]
The answer is silicon.

6 0
3 years ago
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6.285×10^3 mg = _____? _____ kg
TiliK225 [7]
One kilogram is equal to one thousand grams. Further, one gram is equal to 1000 mg. The conversion is as shown below,
                    (6.285 x 10³ mg) x (1 g / 1000 mg) x (1 kg / 1000 g)
The numerical value of the operation above is 0.006285 kg. 
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4 years ago
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1. An electric power plant uses energy from burning coal to generate steam at 450 °C. The plant is cooled by 20 °C water
kap26 [50]

Answer:

Explanation:

Efficiency of the electric power plant is e=1-\frac{T_{2}}{T_{1}}

Here Temperature of hot source T_{1} = 450^{o}C=450+273=723 K

and Temperature of sink T_{1} = 20^{o}C=20+273=293 K

Hence the efficiency is  e=1-\frac{293}{723}=0.5947=59.47%

Now another formula for thermal efficiency Is

e_{therm}=\frac{Q_{1}-Q_{2}}{Q_{1}}=\frac{W}{Q_{1}}

Here QI is the of heat taken from source 100 MJ ; Q2 of heat transferred to the sink (river) to be found

W is the of work done and W = QI -Q2

Hence Frome_{therm}=\frac{Q_{1}-Q_{2}}{Q_{1}}=\frac{W}{Q_{1}}

W=e(Q_{1})=(0.5947)(100)=59.47MJ

Hence the of heat transferred to the river Is Q_{2} -W = (100 -59.47=40.53

6 0
3 years ago
Hans observed properties of four different waves and recorded observations about each one in his chart.
Irina18 [472]

Answer/Explanation:

Wave W is being diffracted, Wave X is being reflected, and waves Y and Z are being refracted.

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