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stepan [7]
3 years ago
15

There is a set table of rate constants for the rate equation. True or false

Physics
1 answer:
Setler [38]3 years ago
4 0

The given statement "There is a set table of rate constants for the rate equation" is true.

Answer: Option A

<u>Explanation:</u>

The rate equation definitely has the need of set of table of rate constants. Rate constants are those which, in a reaction, describe whether it is fast, slow or moderate. And, if a set of rate constants is not available, one may take slow processes and have to wait a long time to predict the results.

And, if the reactions are fast, there is a chance of damage occurring to the surroundings. And since it is a constant, it is easier to determine the products of an intermediate steps, in a chemical reaction too.

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25)Two forces are acting on a block in opposite directions as shown in the figure above
larisa [96]

\boxed{ \sf{Answer}}

____________________

(a) A = 5 kgwt

B = 10 N

First convert 5 kgwt to N,

5 \times 9.8 \\  = 49 \: N

Net force [the forces are acting in 2 opposite directions]

A - B \:  \\  = 49 - 10 \\  = 39 \: N

____________________

(b) Since, the force is greater by A ↦the block will move towards B, i.e, to the <u>right.</u>

____________________

(c) <u>Frictional</u><u> </u><u>force</u><u> </u>will try to oppose the motion of the block but since A has greater force than B, the frictional force will be resisted.

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8 0
3 years ago
What is resultant vector?​
Ann [662]

Answer:

Is the sum of a vector of two or more vectors.

4 0
3 years ago
The terminal velocity of a person falling in air depends upon the weight and the area of the person facing the fluid. Find the t
AVprozaik [17]

Answer:

v=115 m/s

or

v=414 km/h

Explanation:

Given data

A_{area}=0.140m^{2}\\  p_{air}=1.21 kg/m^{3}\\  m_{mass}=80kg

To find

Terminal velocity (in meters per second and kilometers per hour)

Solution

At terminal speed the weight equal the drag force

mg=1/2*C*p_{air}*v^{2}*A_{area}\\   v=\sqrt{\frac{2*m*g}{C**p_{air}*A_{area}} }\\ Where C=0.7\\v=\sqrt{\frac{2*9.8*80}{1.21*0.14*0.7} }\\ v=115m/s

For speed in km/h(kilometers per hour)

To convert m/s to km/h you need to multiply the speed value by 3.6

v=(115*3.6)km/h\\v=414km/h

5 0
3 years ago
In 1656, the Burgmeister (mayor) of the town of Magdeburg, Germany, Otto Von Guericke, carried out a dramatic demonstration of t
kakasveta [241]

The values of the required solutions are

  • F= 53731 N
  • N=37.05

<h3>What is the minimum number of horses required?</h3>

What is Force?

In the field of physics, an influence that can alter the motion of an object is referred to as a force. An object having mass can experience a change in its velocity, often known as an acceleration, when subjected to a force. Intuitively, force can also be conceptualized as either a push or a pull. Because it may be measured in both magnitude and direction, a force is considered a vector quantity.

What is atmospheric pressure?

The pressure that is exerted within the atmosphere of the Earth is referred to as barometric pressure as well as atmospheric pressure. As a unit of pressure, the standard atmosphere is defined as having a value of 101,325 Pa. This value is equivalent to 1013.25 millibars, 760 mm Hg, 29.9212 inches Hg, or 14.696 psi.

In most situations, the equation for force can be expressed numerically as

Force = pressure * A

Therefore

F= (970 - 15 B)(\pi * (0.430 )^2)

F= 53731 N

In conclusion, If each horse can pull with a force of 1450N

The number of horses required is

N=\frac{60754 }{1450}

N=37.05

Read more about Force

brainly.com/question/13191643

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7 0
2 years ago
Which of the following is considered a calm area close to the equator resulting in little to no wind?
solong [7]
<h2>Right answer: Doldrums</h2>

These are also called zones of equatorial calm and it is due a climatic phenomenon that is placed near the Earth equator, attributed to the soft winds, that are called calm winds as well; accompanied by systems of abundant rains and heat.

In this area periods of great calm occur when the winds virtually disappear completely, trapping the sailing ships for long periods (days or weeks). This is why the term <em>doldrum</em> became popular as a colloquial expression in the eighteenth century, to refer to "<em>the caprice of the wind that slows down the navigation to sail". </em>


The zone is located in the place where two trade winds meet, this means the trade winds of the northern hemisphere <u>converge</u> with those of the southern hemisphere, that is why this region is related to the <u>intertropical convergence zone</u>.


5 0
4 years ago
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