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zlopas [31]
4 years ago
13

What is the function of a fixed resistor?

Engineering
1 answer:
agasfer [191]4 years ago
8 0

Answer:

  add resistance to a circuit

Explanation:

It depends on the design in which it is incorporated. A fixed resistor has many uses, including, but not limited to ...

  • dropping voltage
  • limiting current
  • contributing to a time delay
  • adjusting frequency response
  • eliminating (or creating) signal reflections
  • acting as a fuse
  • calibrating or trimming a response
  • providing protection against electrical shock or ESD
  • acting as a reference when measuring variable resistors
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Ideias de nomes para um gato (macho), foto no anexo.​
Rzqust [24]
So cute! xxxxxxxxxxxxxxxxx
4 0
3 years ago
If you think a hazard is serious, what is the best way to ensure that OSHA will
Umnica [9.8K]

Answer:

The best way to ensure that OSHA will conduct a site inspection is by the submission a signed (by a current employee or employee representative) Formal Written complaints following OSHA guidelines (which can be found in the  Council of Safety and Health (COSH) website) which will enable the commencement of process for an on site inspection

As such it is advisable to go through the following procedure before, filing a complaint

1) Talk to your workers union about the hazard

2) If you do not belong to a union, talk to your co-workers

3) Inform your employer who has responsibility for on the job safety

4) Speak or have a meeting with OSHA so as to receive guidance before filing a complaint

Explanation:

3 0
3 years ago
A 1-ft rod with a diameter of 0.5 in. is subjected to a tensile force of 1,300 lb and has an elongation of 0.009 in. The modulus
iragen [17]

Answer:

E = 8.83 kips

Explanation:

First, we determine the stress on the rod:

\sigma = \frac{F}{A}\\\\

where,

σ = stress = ?

F = Force Applied = 1300 lb

A = Cross-sectional Area of rod = 0.5\pi \frac{d^2}{4} = \pi \frac{(0.5\ in)^2}{4} = 0.1963\ in^2

Therefore,

\sigma = \frac{1300\ lb}{0.1963\ in^2} \\\\\sigma = 6.62\ kips

Now, we determine the strain:

strain = \epsilon = \frac{elongation}{original\ length} \\\\\epsilon = \frac{0.009\ in}{12\ in}\\\\\epsilon =  7.5\ x\ 10^{-4}

Now, the modulus of elasticity (E) is given as:

E = \frac{\sigma}{\epsilon}\\\\E = \frac{6.62\ kips}{7.5\ x\ 10^{-4}}

<u>E = 8.83 kips</u>

7 0
3 years ago
What is the relationship between permanent modular construction (PMC) and purpose-built construction?
Vitek1552 [10]

Answer:

A. PMC tends to fit the construction purposes for which it was specifically designed.

Explanation:

took the test go it right

7 0
3 years ago
Air flows through a device such that the stagnation pressure is 0.4 MPa, the stagnation temperature is 400°C, and the velocity i
RoseWind [281]

To solve this problem it is necessary to apply the concepts related to temperature stagnation and adiabatic pressure in a system.

The stagnation temperature can be defined as

T_0 = T+\frac{V^2}{2c_p}

Where

T = Static temperature

V = Velocity of Fluid

c_p = Specific Heat

Re-arrange to find the static temperature we have that

T = T_0 - \frac{V^2}{2c_p}

T = 673.15-(\frac{528}{2*1.005})(\frac{1}{1000})

T = 672.88K

Now the pressure of helium by using the Adiabatic pressure temperature is

P = P_0 (\frac{T}{T_0})^{k/(k-1)}

Where,

P_0= Stagnation pressure of the fluid

k = Specific heat ratio

Replacing we have that

P = 0.4 (\frac{672.88}{673.15})^{1.4/(1.4-1)}

P = 0.399Mpa

Therefore the static temperature of air at given conditions is 72.88K and the static pressure is 0.399Mpa

<em>Note: I took the exactly temperature of 400 ° C the equivalent of 673.15K. The approach given in the 600K statement could be inaccurate.</em>

3 0
3 years ago
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