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12345 [234]
3 years ago
6

Who is the mystical body of Christ

Engineering
2 answers:
Sergeu [11.5K]3 years ago
8 0
If you're talking ab jesus christ , some religions believe it was god in human form and some believe it was gods son it all depends on the religion and how it's taught
iVinArrow [24]3 years ago
5 0

Answer:look at explanation

Explanation:

The mystical body of Christ is The Church is called body, because it is a living entity; it is called the body of Christ, because Christ is its Head and Founder; it is called mystical body, because it is neither a purely physical nor a purely spiritual unity, but supernatural. hope this helps

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Who was first credited with the discovery of the intensity of current within a circuit?
jeyben [28]

Answer:

Hans Christian Ørsted

One of the most important discoveries relating to current was made accidentally by Hans Christian Ørsted in 1820, when, while preparing a lecture, he witnessed the current in a wire disturbing the needle of a magnetic compass.

Explanation:

is that what you were looking for

8 0
3 years ago
The velocity components expressed in m/s<br>​
olchik [2.2K]
The scalar absolute value (magnitude) of velocity is called speed, being a coherent derived unit whose quantity is measured in the SI (metric system) as metres per second (m/s or m⋅s−1). For example, "5 metres per second" is a scalar, whereas "5 metres per second east" is a vector.
3 0
3 years ago
Copy the file DiceSimulation.java (see Code Listing 4.1) from below these instructions. DiceSimulation.java is incomplete. Since
Aliun [14]

Answer:

Program Dice.java

=================================================

import java.util.Random;

public class Dice

{

private int spots; //the number of spots up on the die

private static Random generator;

//a random number generator use simulating rolling dice,

//shared by all dice, so that it will be as random as possible

//constructor creates a single die, inititally with no spots

public Dice()

{

//create an instance of the random

generator = new Random();

spots = 0;

}

//simulates rolling the die and stores the numbers rolled

public void roll()

{

//return 1,2,3,4,5, or 6

spots = generator.nextInt(6) + 1;

}

//return the value of the die

public int getSpots()

{

return spots;

}

}

=========================================================

Program DiceSimulation.java

=========================================================

public class DiceSimulation

{

public static void main(String [] args)

{

final int NUMBER = 10000; //the number of times the roll the dice

Dice die1 = new Dice(); //first die

Dice die2 = new Dice(); //second die

int die1Value; //the number of spots on the second die

int die2Value; //the number of spots on the first die

int count = 0; //number of times the dice were rolled

int snakeEye = 0; //number of times of snakes eyes is rolled

//number of times double two's, three's, four's, five's, six's

int twos = 0;

int threes = 0;

int fours = 0;

int fives = 0;

int sixes = 0;

//ENTER YOUR CODE FOR THE ALGORITHM HERE

for(count=0;count<=NUMBER;count++)

{

die1.roll();

int t1=die1.getSpots();

die2.roll();

int t2=die2.getSpots();

if(t1==t2)

{

if(t1==1)snakeEye++;

else if(t1==2)twos++;

else if(t1==3)threes++;

else if(t1==4)fours++;

else if(t1==5)fives++;

else if(t1==6)sixes++;

}

}

count--;

//output to console

System.out.println("You rolled snake eyes " + snakeEye

+ " out of " + count + " rolls.");

System.out.println("You rolled double two " + twos

+ " out of " + count + " rolls.");

System.out.println("You rolled double threes " + threes

+ " out of " + count + " rolls.");

System.out.println("You rolled double fours " + fours

+ " out of " + count + " rolls.");

System.out.println("You rolled double fives " + fives

+ " out of " + count + " rolls.");

System.out.println("You rolled double sixes " + sixes

+ " out of " + count + " rolls.");

}

}

========================================================

Sample output:

5 0
3 years ago
Steam at a pressure of 0.08 bar and a quality of 93.2% enters a shell-and-tube heat exchanger where it condenses on the outside
Semenov [28]

Answer:

The answer is "\bold{9.09\times 10^6 \frac{kg}{hour}}".

Explanation:

For the reference table we get:

h1 = 2410 \frac{kJ}{kg} \ , at \ \ \\\\ \ P = 0.08 \ bar \ and \ \ quality = 0.932

Through steam tables, they get:

\ h2 = 173.9 \frac{kJ}{kg} \ on\\\\ \ P = 0.08 \ bars \ \ \ but \ quality = 0 (sat.liquid),

Water power transfer = \ 3.4 \times  10 ^ 5 \times  (2410-173.9)\\

It should be comparable to the water enthalpy:

m_{water}\times Cp\times (T2-T1)\\\\For \ eg:\\\\ = 3.4 \times 10 ^ 5\times (2410-173.9) \\\\ = m_{water}\times4.18\times(35-15)\\  

m_{water}=9.09\times 10^6 \frac{kg}{hour}

4 0
3 years ago
A bullet weighing 0.08 lb is fired with a horizontal velocity of 1800 ft/s into the lower end of a slender 23-lb bar of length L
Sergeeva-Olga [200]

Answer: hello attached below is the missing image the slender weight is different from what is in the question here so I worked with 23-Ib as requested in the question

answer

≈ 12.17 Rad/sec

Explanation:

weight of bullet ( Wb ) = 0.08 Ib

horizontal velocity = 1800  ft/s

Slender(Wr) = 23-Ib bar with

length ( L ) = 30

h = 12 inches

Vro = 0

<u>Calculate the angular velocity of the bar immediately after the bullet becomes embedded  </u>

attached below is a detailed solution

6.708 = ( 0.05011 + 0.5011 ) w'

w' = 6.708 / 0.55121 ≈ 12.17 Rad/sec

6 0
3 years ago
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