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snow_lady [41]
3 years ago
13

If a steady magnetic field exerts a force on a moving charge, that force is directed

Physics
1 answer:
lesya [120]3 years ago
4 0

Answer:

C) at right angles to the direction of the motion

Explanation:

The magnetic force exerted on a charged moving particle is given by

F=qvBsin \theta

where

q is the charge of the particle

v is the velocity of the particle

B is the magnetic field intensity

\theta is the angle between the direction of v and B

Moreover, the direction of the force is perpendicular to both v and B. In particular, the direction can be found by using the right hand rule:

- index finger: direction of the velocity

- middle finger: direction of the magnetic field

- thumb: direction of the force (if the charge is positive, otherwise the direction must be reversed if the charge is negative)

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In a 100 mm diameter horizontal pipe, a venturimeter of 0.5 contraction ratio has been fitted. The head of water on the meter wh
nata0808 [166]

Answer:

the rate of flow = 29.28 ×10⁻³ m³/s or 0.029 m³/s

Explanation:

Given:

Diameter of the pipe = 100mm = 0.1m

Contraction ratio = 0.5

thus, diameter at the throat of venturimeter = 0.5×0.1m = 0.05m

The formula for discharge through a venturimeter is given as:

Q=C_d\frac{A_1A_2}{\sqrt{A_1^2-A_2^2}}\sqrt{2gh}

Where,

C_d is the coefficient of discharge = 0.97 (given)

A₁ = Area of the pipe

A₁ = \frac{\pi}{4}0.1^2 = 7.85\times 10^{-3}m^2

A₂ = Area at the throat

A₂ = \frac{\pi}{4}0.05^2 = 1.96\times 10^{-3}m^2

g = acceleration due to gravity = 9.8m/s²

Now,

The gauge pressure at throat = Absolute pressure - The atmospheric pressure

⇒The gauge pressure at throat = 2 - 10.3 = -8.3 m (Atmosphric pressure = 10.3 m of water)

Thus, the pressure difference at the throat and the pipe = 3- (-8.3) = 11.3m

Substituting the values in the discharge formula we get

Q=0.97\frac{7.85\times 10^{-3}\times 1.96\times 10^{-3}}{\sqrt{7.85\times 10^{-3}^2-1.96\times 10^{-3}^2}}\sqrt{2\times 9.8\times 11.3}

or

Q=\frac{0.97\times15.42\times 10^{-6}\times 14.88}{7.605\times 10^{-3}}

or

Q = 29.28 ×10⁻³ m³/s

Hence, the rate of flow = 29.28 ×10⁻³ m³/s or 0.029 m³/s

7 0
3 years ago
Help on these 2 pls ASAP!!!!!!<br><br> BTW ITS A SCI QUESTION
kenny6666 [7]

Answer:

Net force

I think it’s balanced force

3 0
3 years ago
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\vec F = I (\vec L \times  \vec B)

if currents go in opposite directions, wires repel
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You are trying to find the amount of heat transferred between two substances. In order to do this, you plan
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Answer:

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Explanation:

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Answer:

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