Hope this shows! It has all the equations for all of the problems u asked in the comments
<span>A motor produces less mechanical energy than the energy it uses because the motor looses some energy to heat.</span>
Answer:
Charge on each metal sphere will be 
Explanation:
We have given number of electron added to metal sphere A 
As both the spheres are connected by rod so half -half electron will be distributed on both the spheres.
So electron on both the spheres 
We know that charge on each electron 
So charge on both the spheres will be equal to 
So charge on each metal sphere will be equal to 
Answer:

Explanation:
The energy of a single photon is given by:

where
h is the Planck constant
c is the speed of light
is the wavelength
For the photon in this problem,

So, its energy is

One mole of photons contains a number of photons equal to Avogadro number:

So, the total energy of one mole of photons is

The volume decreases, by a factor of
(the original pressure/(125 kPa).