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avanturin [10]
3 years ago
8

Here is a graph of speed vs time. If the object is moving to the east, which BEST describes the speed and velocity of the graph?

Group of answer choices Both speed and velocity are changing. The speed and velocity remain constant. The speed is constant and velocity is changing. The speed is constant and velocity is changing.

Physics
1 answer:
Artemon [7]3 years ago
5 0

Answer:

Both speed and velocity are changing.

Explanation:

They are both going up so both are changing

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A guy wire 1005 feet long is attached to the top of a tower. When pulled taut, it touches level ground 552 feet from the base of
trasher [3.6K]

Answer:

56.7°

Explanation:

Imagine a rectangle triangle.

The triangle has 3 sides.

One side is the height of the tower, let's name it A.

Another side is the distance from the base of the tower to the point where the waire touches the ground. Let's name that B.

Sides A and B are perpendicular.

The other side is the length of the wire. Let's name it C.

From trigonometry we know that:

cos(a) = B / C

Where a is the angle between B anc C, between the wire and the ground.

Therefore

a = arccos(B/C)

a = arccos(552/1005) = 56.7°

7 0
3 years ago
Light that has a wavelength of 554 nm is incident on a single slit that is 10 μm wide. Determine the angular location of the fir
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66.3 = 3% 9.528 correct 3.176 correct
7 0
3 years ago
In a fast-pitch softball game the pitcher is impressive to watch, as she delivers a pitch by rapidly whirling her arm around so
Pepsi [2]

Answer:

(a) 181.05 m/s²

(b) 13.2°

Explanation:

Given:

Radius of the circle (R) = 0.610 m

Angular acceleration (α) = 67.6 rad/s²

Angular speed (ω) = 17.0 rad/s

(a)

Radial acceleration of the ball is given as:

a_r=\omega^2R

Plug in the given values and solve for a_r. This gives,

a_r=(17.0\ rad/s)^2\times (0.610\ m)\\\\a_r=289\times 0.610\ m/s^2\\\\a_r=176.29\ m/s^2

Now, tangential acceleration is given by the formula:

a_t=R\alpha

Plug in the given values and solve for a_t. This gives,

a_t=(0.610\ m)(67.6\ rad/s^2)\\\\a_t=41.236\ m/s^2

Now, the magnitude of total acceleration is given as the square root of the sum of the squares of tangential and centripetal accelerations. Therefore,

a_{Total}=\sqrt{(a_r)^2+(a_t)^2}

Plug in the given values and solve for total acceleration, a_{Total}. This gives,

a_{Total}=\sqrt{(176.29)^2+(41.236)^2}\\\\a_{Total}=181.05\ m/s^2

Therefore, the magnitude of total acceleration is 181.05 m/s².

(b)

Angle of total acceleration relative to radial direction is given by the formula:

\theta=\tan^{-1}(\frac{a_t}{a_r})\\\\\theta=\tan^{-1}(\frac{41.236}{176.29})\\\\\theta=13.2\°

Therefore, the total acceleration makes an angle of 13.2° relative to radial direction.

4 0
3 years ago
State the term using to describe the turning force force exerted by the man
defon

Answer:

The distance between the line of action of force and the axis of rotation (or pivoted point)

Explanation:

The distance between the line of action of force and the axis of rotation (or pivoted point) .

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3 years ago
It is the year 802,315 and due to the sun growing, Earth is starting to get too hot for life to survive. Oceans are beginning to
Paha777 [63]

Answer:

Explanation:

We will die soon anyway we all die

4 0
3 years ago
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