Answer:
No we can’t cover the earth with one mole of pennies
Explanation:
We can’t cover the earth with one mole of pennies due to the fact that making this possible will require the flattening and extra expansion before it covers the whole surface.
The extra expansion and flattening with result in the loss of intermolecular forces and won’t remain as a solid and form other states of matter which won’t be able to cover the surface.
Answer:
The density.
Explanation:
The density is an intensive property of fluids, defined as mass divided by volume.
This property is directly related to the intermolecular forces that are present in the substance: the stronger the intermolecular forces, the higher the density will be, and viceversa. Therefore, organic fluids usually have lower densities than water, because <u>the intermolecular forces in organic fluids are not as strong as in the intermolecular forcer in water</u> (water has very stable hydrogen bonds, whereas organic fluids have van der Waals, weaker than hydrogen bonds).
The liquid that has the lower density will be the the liquid that is on the top layer. In this case, the organic compound tert-butyl methyl ether will be on top of water.
Answer:
Here's what I get
Explanation:
I don't know what the notation on page 91 is (COO⁻?), but your diagram should be something like the one below.
The stearate tails are immersed in and pointing to the centre of the green oil glob.
The negative heads are on the surface surrounded by water molecules.
You may have to draw them as COO⁻.
The rate of a reaction decreases as the reaction progresses.
Answer:
153.3 grams of ZrCl₄ are produced
Explanation:
The equation of the reaction is as follows:
ZrSiO₄ + Cl₂ ----> ZrCl₄ + SiO₂ + O₂
molar mass of ZrSiO₄ = (91 + 32 + 16 * 4) = 187.0 g/mol
molar mass of ZrCl₄ = (91 + 35.5 * 4) = 233.0 g/mol
molar mass of Cl₂ = (35.5 * 2) 71.0 g/mol
From the equation of reaction, 1 mole of ZrSiO₄ reacts with one mole of Cl₂ to produce one mole of ZrCl₄
number of moles of ZrSiO₄ present in 123 g = 123/187 = 0.65 moles
number of moles of Cl₂ present in 85.0 g = 85.0/71.0 = 1.19 moles
therefore, ZrSiO₄ is the limiting reactant
123.0 g of ZrSiO₄ will react with excess Cl₂ to produce 123 * 233/187 grams of ZrCl₄ = 153.3 grams of ZrCl₄
Therefore, 153.3 grams of ZrCl₄ are produced