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3 years ago

How is the energy of the wave affected if the amplitude of the wave increases from 2 meters to 4

Physics

1 answer:

Alex777 [14]3 years ago

5 0

Answer:

Energy of wave will increase as the energy of wave is related to the amplitude of wave

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A pendulum is transported from sea-level, where the acceleration due to gravity g is 9.80 m/s2, to the bottom of Death Valley. A

tatyana61 [14]

Answer: the value of g in Death Valley is 10.417 m/s²

Explanation:

Given that;

acceleration due to gravity at the point is g = 9.8 m/s²

Lets say the acceleration due to gravity at the bottom of Death valley is g'

as the period of the pendulum is decreased by 3.00%

T' = 0.97 T

T is the period of the pendulum at sea level and T' is the period of the pendulum at bottom of Death valley

therefore from the relation

T = 2π√(l/g)

g'/g = T²/T'²

g' = (T²/ (0.97T)²)g

g' = 1.063g

g' = 10.417 m/s²

therefore the value of g in Death Valley is 10.417 m/s²

7 0

3 years ago

You want the current amplitude through a 0.450-mH inductor (part of the circuitry for a radio receiver) to be 1.90 mA when a sin

faust18 [17]

Answer:

Frequency required will be 2421.127 kHz

Explanation:

We have given inductance $L=0.450H=0.45\times 10^{-3}H$

Current in the inductor $i=1.90mA=1.90\times 10^{-3}A$

Voltage v = 13 volt

Inductive reactance of the circuit $X_l=\frac{v}{i}$

$X_l=\frac{13}{1.9\times 10^{-3}}=6842.10ohm$

We know that

$X_l=\omega L=2\pi fL$

$2\times 3.14\times f\times 0.45\times 10^{-3}=6842.10$

f = 2421.127 kHz

6 0

3 years ago

A simple pendulum having a length of 1.02 m and a mass of 6.66 kg undergoes simple harmonic motion when given an initial speed o

attashe74 [19]

Answer:

Time period of pendulum is 2.02 s.

Explanation:

A simple pendulum is a device which consists of mass m hanging from the string of length L attached to the some point.When displaced and released its swings back and forth with periodic motion.

The time period of pendulum is defined as time taken by the pendulum to complete one full oscillation . it is denoted by T.

By Huygens law of period of pendulum,

T = 2π $\sqrt{\frac{L}{g} }$ eqn 1

where L is the length of pendulum,

g is acceleration due to gravity

Period of pendulum is independent of the mass of pendulum,

Substituting values in eqn 1

T = 2π $\sqrt{\frac{1.02}{9.8\\} }$

T = 2.02 s

Time period of pendulum is 2.02 s.

4 0

3 years ago

H e l p a h o m i e o u t t h a n k s

finlep [7]

Uh it’s D i’m pretty sure

4 0

3 years ago

Suppose that you hear a clap of thunder 16.2 s (seconds) after seeing the associated lightning stroke. The speed of sound waves

spayn [35]

Since the speed of sound is very high, we consider the time period of thunder and lightening negligible.

Now, d = vt

thus, d = 343 x 16.2

thus, d = 5556.6 metres

Thus, we are 5556.6 metres away from lightening ( approximately)

5 0

3 years ago