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Rudik [331]
3 years ago
11

Water from a river or reservoir enters a hydroelectric power plant through a.....????

Physics
2 answers:
crimeas [40]3 years ago
8 0

Answer:

penstock

Explanation:

i am doing the test now.

JulijaS [17]3 years ago
5 0
Through a dam... hope this helps:)
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NEED HELP NOW. I WILL BRAINLIEST
NeTakaya

Answer:

number of Protons=16

number of Neutrons=16

number of electrons=32

Explanation:

Tip:-

<em><u>Always the number of protons = the number of neutrons.</u></em>

<em><u>Add them and you will get the number of electrons.</u></em>

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2 years ago
6. Willingness to take turns is one way we can express our attitudes in
NNADVOKAT [17]
The answer is A ..........
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What are 3 things that can affect gravity?
den301095 [7]
The force of gravity the masses exert on each other. If one of the masses is doubled , the force of gravity between the objects is doubled. Increases , the force of gravity decreases.
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2 years ago
Jon's bathtub is rectangular and its base is 18 ft2. (a) How fast is the water level rising if Jon is filling the tub at a rate
Kitty [74]

Answer:

The water level in the bath tub is rising at a rate of 0.0111 ft/s

Explanation:

Volume of the bath tub = (Area of base) × (height)

Area of base = 18 ft² (constant)

Height = h (variable)

V = 18h

(dV/dt) = 18 (dh/dt)

If (dV/dt) = 0.2 ft³/s

0.2 = 18 (dh/dt)

(dh/dt) = (0.2/18)

(dh/dt) = 0.0111 ft/s

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6 0
3 years ago
Read 2 more answers
The engine in an imaginary sports car can provide constant power to the wheels over a range of speeds from 0 to 70 miles per hou
puteri [66]

Answer:

t=5.3687\ s  is the time taken by the car to accelerate the desired range of the speed from zero at full power.

Explanation:

Given:

Range of speed during which constant power is supplied to the wheels by the car is 0\ mph\ to\ 70\ mph.

  • Initial velocity of the car, v_i=0\ mph
  • final velocity of the car during the test, v_f=32\ mph=14.3052\ m.s^{-1}
  • Time taken to accelerate form zero to 32 mph at full power, t=1.2\ s
  • initial velocity of the car, u_i=0\ mph
  • final desired velocity of the car, u_f=64\ mph=28.6105\ m.s^{-1}

Now the acceleration of the car:

a=\frac{v_f-v_i}{t}

a=\frac{14.3052-0}{1.2}

a=11.921\ m.s^{-1}

Now using the equation of motion:

u_f=u_i+a.t

64=0+11.921\times t

t=5.3687\ s is the time taken by the car to accelerate the desired range of the speed from zero at full power.

8 0
3 years ago
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