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3 years ago

Water from a river or reservoir enters a hydroelectric power plant through a.....????

Physics

2 answers:

crimeas [40]3 years ago

8 0

Answer:

penstock

Explanation:

i am doing the test now.

JulijaS [17]3 years ago

5 0

Through a dam... hope this helps:)

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A particle at 9 AM is moving towards the east at 4 ms At 12 noon, it changes its velocity and starts moving towards the north un

nexus9112 [7]

Answer:

Explanation:

Acceleration is the time rate of change of velocity.

Acceleration and velocity are vectors

If east and north are the positive directions, the east moving vector is reduced to zero and the north moving vector increases from zero to 4 m/s.

There are 3 hours or 10800 seconds between 10 AM and 1 PM

a1 = √((-4)² + 4²) / 10800 = (√32) / 10800 m/s² ≈ 4.2 x 10⁻⁴ m/s²

There are 14400 seconds between 10 AM and 2 PM

The velocity changes are still the same

a2 = √((-4)² + 4²) / 10800 = (√32) / 14400 m/s² ≈ 3.9 x 10⁻⁴ m/s²

7 0

3 years ago

A merry-go-round with a a radius of R = 1.99 m and moment of inertia I = 194 kg-m2 is spinning with an initial angular speed of

Aleksandr [31]

Answer:

Part 1)

$L_1 = 185.2 kg m^2/s^2$

Part 2)

$L_2 = 663.07 kg m^2/s^2$

Part 3)

$L = 663.07 kg m^2/s^2$

Part 4)

$\omega = 1.83 rad/s$

Part 5)

$F_c = 453.6 N$

Explanation:

Part a)

Initial angular momentum of the merry go round is given as

$L_1 = I \omega$

here we know that

$I = 194 kg m^2$

$\omega = 1.47 rad/s^2$

now we have

$L_1 = 194 \times 1.47$

$L_1 = 185.2 kg m^2/s^2$

Part b)

Angular momentum of the person is given as

$L = mvR$

so we have

$m = 68 kg$

$v = 4.9 m/s$

R = 1.99 m

so we have

$L_2 = (68)(4.9)(1.99)$

$L_2 = 663.07 kg m^2/s^2$

Part 3)

Angular momentum of the person is always constant with respect to the axis of disc

so it is given as

$L = 663.07 kg m^2/s^2$

Part 4)

By angular momentum conservation of the system we will have

$L_1 + L_2 = (I_1 + I_2)\omega$

$185.2 + 663.07 = (194 + 68(1.99^2))\omega$

$848.27 = 463.28 \omega$

$\omega = 1.83 rad/s$

Part 5)

Force required to hold the person is centripetal force which act towards the center

so we will have

$F_c = m\omega^2 R$

$F_c = 68(1.83^2)(1.99)$

$F_c = 453.6 N$

3 0

3 years ago

Hi, i know that this isnt neces sary. but can anyone request a ga mes for me, im bo red. thankyou.

Stella [2.4K]

Answer:

genshin impact. the same level. and AdCap

5 0

3 years ago

Read 2 more answers

A body of mass 5kg is taken from height 10m. find the increase in potential energy

Vadim26 [7]

Answer:

500 joule

Explanation:

given,

mass(m)= 5kg

height(h)= 10m

acceleration due to gravity(g)= 10m/s^2

potential energy =?

We know that,

potential energy = mgh

= 5×10×10

= 500 joule

3 0

3 years ago

Write the equation for newtons third law

Ganezh [65]

Answer:

Explanation:

Newtons third law says an applied force will produce an equal but opposite force.

$F_A_B =-F_B_A$

8 0

3 years ago