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tekilochka [14]

3 years ago

11

Carla did an experiment by placing a piece of smooth, clear glass and a piece of smooth, black stone under a lamp for twenty min

utes. Which prediction will most likely be supported by Carla’s experimental results?

1 answer:

goldenfox [79]3 years ago

6 0

Answer:

The stone will feel warmer than the glass after twenty minutes.

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A force of 20N changes the position of a body. If mass of the body is 2kg, find the acceleration produced in the body.2. A ball

shepuryov [24]

Explanation:

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<em>v</em><em>=</em><em> </em><em>velocity</em><em>.</em>

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5 0

4 years ago

The Sun is about 150 million km from earth. how long does it take light from the sun to reach earth? (Speed of light is 3x10^8m/

madam [21]

Time =      (distance) / (speed)

Time = (150 x 10⁹ m) / (3 x 10⁸ m/s) =

   50 x 10¹ sec =

       <em>500 sec</em> = 8 min 20 sec

3 0

4 years ago

What H & N can friction produce?

Angelina_Jolie [31]

Friction produces heat hope this helps

5 0

3 years ago

The horizontal bar rises at a constant rate of three hundred mm/s causing peg P to ride in the quarter circular slot. When coord

SVETLANKA909090 [29]

Answer:

Explanation:

Given

Horizontal bar rises with 300 mm/s

Let us take the horizontal component of P be

$P_x=rcos\theta$

$P_y=rsin\theta$

where $\theta$ is angle made by horizontal bar with x axis

Velocity at y=150 mm

$150=300sin\theta$

thus $\theta =30^{\circ}$

position of $P_x=rcos\theta =300\cdot cos30=300\times \frac{\sqrt{3}}{2}$

$P_x=259.80 mm$

$P=259.80\hat{i}+150\hat{j}$

Velocity at this instant

$u_x=-rsin\theta =300\times sin30=-150 mm/s$

$u_y=rcos\theta =300\times cos30=259.80 mm/s$

4 0

3 years ago

Two children are riding on a merry-go-round that is rotating with a constant angular speed. Abbie is one meter from the center o

klio [65]

Answer:

The acceleration of Abbie is half of the Zak's.

Explanation:

The centripetal acceleration of an object on a circular path is given by :

$a=r\omega^2$

Two children are riding on a merry-go-round that is rotating with a constant angular speed. Let $r_1$ is distance of Abbie from the merry-go-round and $r_2$ is distance of Zak's from the merry-go-round. Acceleration of Abbie is :

$a_1=r_1\omega^2$ ...... (1)

$r_1=1\ m$

Acceleration of Zak's is :

$a_2=r_2\omega^2$ .......(2)

$r_2=2\ m$

Dividing equation (1) and (2) we get :

$\dfrac{a_1}{a_2}=\dfrac{r_1}{r_2}\\\\\dfrac{a_1}{a_2}=\dfrac{1}{2}\\\\a_1=\dfrac{a_2}{2}$

So, the acceleration of Abbie is half of the Zak's.

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3 years ago