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oee [108]
3 years ago
6

A certain reaction has an activation energy of 39.5 kJ/mol. As the temperature is increased from 25.0°C to a higher temperature,

the rate constant increases by a factor of 5.90. Calculate the higher temperature (in °C).
Chemistry
1 answer:
riadik2000 [5.3K]3 years ago
4 0

Answer:

Explanation:

We shall apply Arrhenius equation which is given below .

ln\frac{k_2}{k_1} = \frac{E_a}{R} [\frac{1}{T_1} -\frac{1}{T_2} ]

K₂ and K₁ are rate constant at temperature T₂ and T₁ , Ea is activation energy .

Putting the given values

ln\frac{5.9}{1} = \frac{39500}{8.3} [\frac{1}{298} -\frac{1}{T_2} ]

.000373= [\frac{1}{298} -\frac{1}{T_2} ]

T₂ = 335.27 K

= 62.27 °C

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2. Calculate the mass of K in 90g of KOH​
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The table below lists some properties of a sample of lauric acid.
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2 years ago
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When 21.5 g of CH4 gas reacts with 387.5 g O2 gas, how much CO2 is formed?
Doss [256]

Answer:

Mass = 58.96 g

Explanation:

Given data:

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Mass of CO₂ formed = ?

Solution:

Chemical equation:

CH₄ + 2O₂       →   CO₂ +  2H₂O

Number of moles of CH₄:

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                       O₂             :          CO₂

                          2             :            1

                          12.1          :          1/2×12.1 = 6.05 mol

                        CH₄          :          CO₂

                           1              :            1

                          1.34           :         1.34

Number of moles of CO₂ produced by  CH₄ are less thus it will limiting reactant.

Mass of  CO₂:

Mass = number of moles × molar mass

Mass =  1.34 mol × 44 g/mol

Mass = 58.96 g

8 0
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fomenos

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