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3 years ago

9

You are a scientist and would like to know if anew fertilizer will help plants grow faster. What would the experimental group be

?
The plants that only get water
The plants that get different amounts of the new fertilizer
The plants that only get soil

1 answer:

Gennadij [26K]3 years ago

6 0

Answer:

The plants that get different amounts of the new fertilizer.

if my answer helps you than mark me as brainliest.

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Suppose that a block is pulled 16 meters across a floor. What amount of work is done if the force used to drag the block is 22 N

klemol [59]

We have: A= F.s
So, A = 22 x 16
A= 352J
Só A is correct answer

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3 years ago

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The blade of a windshield wiper moves through an angle of 180.0 degrees in 0.500 s. The tip of the blade moves on the arc of a c

sweet-ann [11.9K]

Answer:

Centripetal acceleration will be equal to $10.66m/sec^2$

Explanation:

We have given time taken to cover 180° is 0.5 sec

So time taken by 360° is equal to = 2×0.5 = 1 sec

Radius of the circle r = 0.520 m

So distance $d=2\pi r=2\times3.14\times 0.520=3.2656m$

So velocity $v=\frac{distance}{time}=\frac{.2656}{1}=3.2656m/sec$

We have to find the centripetal acceleration

Centripetal acceleration will be equal to $a_c=\frac{v^2}{r}=\frac{3.2656^2}{1}=10.66m/sec^2$

So centripetal acceleration will be equal to $10.66m/sec^2$

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4 years ago

You push a desk with 230 N, but the desk doesn't move due to its friction with the ground. What is the magnitude of the friction

ASHA 777 [7]

Answer:

$force \: = friction \: based \: on \: newtons \: third \: law \\ \: f = |230| = 230 \: newton \\ this \: is \: why \: the \: desk \: \\ doesnt \: move...$

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3 years ago

Savvas realize hot on the inside

Liula [17]

Answer:

Thats sounds like a club

Explanation:

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3 years ago

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A 1-kg discus is thrown with a vertical velocity of 19 m/s at an angle of 35 degrees from a height of 1.94 m. Do not factor in a

Travka [436]

Answer:

Vertical velocity $V_y = 10.89 \ m/s$

Horizontal velocity $V_x = 15.57 \ m/s$

Explanation:

If a 1 -kg is thrown vertically with a velocity of 19 m/s at an angle of 35 °C from a height 1.94 m

The vertical and horizontal component can be resolved as:

$V_y = Vsin \theta \\ \\ \\\\V_x = Vcos \theta$

For Vertical component :

$V_y = V sin \theta \\\\V_y = 19 * sin 35 \\ \\ V_y = 19* 0..5736 \\ \\ V_y = 10.89 \ m/s$

For horizontal velocity

$V_x = V cos \theta \\\\V_x = 19 * cos 35 \\ \\ V_x = 19* 0.8192 \\ \\ V_x = 15.57 \ m/s$

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3 years ago