Answer:
L_new =L+x^2 = L_new = 0.54_m.
Explanation:
Given data:
Force in the first case,
F_1 = 5N
Force in the second case,
F_2 = 20 N
Natural length of spring,
L= 0.5
Extension in the first case,
x_1 = 0.01m
Let the force constant of the spring be k.
Thus,
F_1=kx_1
5 = k × 0.01
⇒ k = 500 N/m.
The extension in the spring in the second case can be given as,
F_2=kx_2
20 = 500x_2
⇒ x_2 = 0.04 m.
Thus, the effective length of the spring would be,
L_new =L+x^2
L_new = 0.5+0.04
L_new = 0.54_m.
<u>Answer:</u>
At time 2t the paint ball is at 8 cm to the right and 16 cm to the bottom
<u>Explanation:</u>
We have equation of motion ,
, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.
Considering the horizontal motion of paint ball
Distance traveled during time t = 4 cm
Initial velocity = u m/s
Acceleration = 0 
So 
Now at time 2t,

So horizontal distance traveled in time 2t = 8 cm to the right
Now considering the vertical motion of paint ball
Distance traveled during time t = 4 cm
Initial velocity = 0 m/s
Acceleration = -g 

At time 2t,

So vertical distance traveled in time 2t = 16 cm to the bottom
Answer:
kinetic energy
Explanation:
we are using chemical energy in our bodies to produce movement, whitch in turn convents to warmth.
Answer:
(a) 0
(b) 10ML
(c) 
(d) 
Explanation:
(a) When hanging straight down. The child is at the lowest position. His potential energy with respect to this point would also be 0.
(b) Since the rope has length L m. When the rope is horizontal, he is at L (m) high with respect to the lowest swinging position. His potential energy with respect to this point should be

where g = 10m/s2 is the gravitational acceleration.
(c) At angle
from the vertical. Vertically speaking, the child should be at a distance of
to the swinging point, and a vertical distance of
to the lowest position. His potential energy to this point would be:

(d) at angle
from the horizontal. Suppose he is higher than the horizontal line. This would mean he's at a vertical distance of
from the swinging point and higher than it. Therefore his vertical distance to the lowest point is 
His potential energy to his point would be:
