Answer:
1.09 grams
Explanation:
According to the following chemical equation:
HF + NaNO₃ -> HNO₃ + NaF
1 mol of hydrogen fluoride (HF) produces 1 mol of sodium fluoride (NaF). Thus, we first convert from mol to grams by using the molar mass (MM) of each compound:
MM(HF)= (1 g/mol x 1 H) + (19 g/mol x 1 F) = 20 g/mol HF
1 mol HF x 19.9 g/mol HF = 20 g
MM(NaF) = (23 g/mol x 1 Na) + (19 g/mol x 1 F) = 42 g/mol NaF
1 mol NaF x 42 g/mol NaF = 42 g
Thus, from 20 g of HF are produced 42 g of NaF ⇒ 20 g HF/42 g NaF. We multiply this stoichiometric ratio by the mass of NaF produced to calculate the required mass of HF:
20 g HF/42 g NaF x 2.3 g NaF = 1.09 g HF
Therefore, 1.09 grams of HF are necessary to produce 2.3 g of NaF.
Answer:
N2O5
Explanation:
IUPAC ID: Dinitrogen pentoxide
Molar mass: 108.01 g/mol
Density: 1.64 g/cm³
Answer:
After increasing the volume, we have 1.81 moles of hydrogen gas in the container
Explanation:
Step 1: Data given
Number of moles hydrogen gas (H2) = 1.24 moles
Volume of hydrogen gas (H2° = 27.8 L
The final volume is increas to 40.6 L
Step 2: Calculate the new number of moles
V1/n1 = V2/n2
⇒with V1 = the initial volume = 27.8 L
⇒with n1 = the initial number of moles H2 = 1.24 moles
⇒with V2 = the final volume = 40.6 L
⇒with n2 = the new number of moles = TO BE DETERMINED
27.8L / 1.24 moles = 40.6 L / n2
n2 = 40.6 / (27.8/1.24)
n2= 1.81 moles
After increasing the volume, we have 1.81 moles of hydrogen gas in the container
Chemsits identify elements and compounds by using the Periodic Table. All elements have Atomic Numbers, Chemical Names, Atomic Mass, Period, and are usually colored and put into their group.
