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Karolina [17]
3 years ago
15

Approximately how many kelvins are equal to 60°c?

Physics
2 answers:
ella [17]3 years ago
8 0

333.15 Kelvins are equal to 60 degrees celsius

Scrat [10]3 years ago
3 0

0°C = 273.15 K

Kelvin = °C + 273.15

<em>60°C = 333.15 K</em>

If you only want it approximately, then call it  333K .

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Answer:

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2 ( s )

Explanation:

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4 years ago
A car traveling west in a straight line on a highway decreases its speed from 30 meters per second to 23 meters per second in 2
garik1379 [7]
U1= 30m/s
u2= 23m/s
t=2s
a=(u2-u1)/t
a=-7/2=-3.5 m/s^2
6 0
3 years ago
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A runner begins running at the beginning of 7th period and stops running at the end of the period. She runs at a pace of 10 km/h
MrRissso [65]

Answer:

She run for, t = 0.92 s

Explanation:

Given data,

The velocity of the runner, v = 10 km/h

The distance covered by the runner, d = 9.2 km

The relationship between the velocity, displacement and time is given by the formula,

                           t = d / v

Substituting the given values in the above equation,

                           t = 9.2 / 10

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Hence, she ran for, t = 0.92 s

8 0
3 years ago
If the sun were to vanish instantly would earth immediately fly out of its orbit explain why or why not
Zanzabum
<span>Answer: No, because Einstein demonstrated that nothing can exceed the speed of light in a vacuum and for something to happen instantly over that distance would require that speed to be exceeded. If somehow the sun were to vanish, without explosive effects, an enormous gravity wave would begin travelling outward affecting the planets at the speed of light - thus taking about 8 minutes to reach earth. But that is irrelevant because the only way to remove all that matter would be total conversion of the mass to energy and that energy would totally destroy everything - after the same 8 minutes. Mike1942f · 9 years ago</span>
7 0
3 years ago
Use Newton's laws to explain why a falling object dropped from a 57m tower accelerates initially but then reaches constant veloc
snow_lady [41]

Answer:

At the point of dropping the object, by Newton's first law due to gravitational force F_g = m × g, accelerates

By Newton's Second law the object reaches impacts on the air with the gravitational force resulting in changing momentum of m×(Final Velocity - Initial Velocity)

As the velocity increases, the rate of change of momentum becomes equivalent to the gravitational force and by Newton's third law, the action action and reaction are equal and opposite hence they cancel each other out

The body then moves at a constant uniform motion down according to Newton's first law

Explanation:

At the point the object of mass, m, is dropped from the height of the tower, the only force acting on the object is the gravitational force such that the object has an acceleration which is the acceleration due to gravity, g, and the gravitational force is therefore = m × g

As the speed of the object increases while the object is falling with the gravitational acceleration the rate at which the object cuts through layers of air which (by Newton's first law of motion, are at rest ) has some buoyancy effect also increases therefore, the object is constantly increasingly changing the momentum of the air which by Newton's second law results, at an high enough velocity, and by Newton's third law, in a force equal to the applied gravitational force

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5 0
3 years ago
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