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2 years ago

What types of media can S-waves travel through

Physics

1 answer:

Greeley [361]2 years ago

5 0

Answer:

The second type of body wave is the S wave or secondary wave, which is the second wave you feel in an earthquake. An S wave is slower than a P wave and can only move through solid rock, not through any liquid medium.

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In most food chains all of the energy originally comes from

ch4aika [34]

All of the original energy comes from the sun

8 0

2 years ago

A planet orbits a star, in a year of length 2.35 x 107 s, in a nearly circular orbit of radius 3.49 x 1011 m. With respect to th

Naya [18.7K]

Answer:

a) w = 9.599 10⁴ rad / s , b) v = 3.35 10¹⁶ m / s , c) a = 3.22 10²¹ m / s²

Explanation:

For this exercise we must use the relation of angular kinematics

a) angular velocity, the distance remembered in orbit between time (period)

w = 2π r / T

w = 2 π 3.59 10¹¹ / 2.35 10⁷

w = 9.599 10⁴ rad / s

b) linear and angular velocity are related by the equation

v = w r

v = 9,599 10⁴ 3.49 10¹¹

v = 3.35 10¹⁶ m / s

c) the centripetal acceleration is

a = v² / r = w² r

a = (9,599 10⁴)² 3.49 10¹¹

a = 3.22 10²¹ m / s²

7 0

2 years ago

A 0.80-kg soccer ball experinces an impulse of 25 N x s . Determine the momentum change of the soccer ball.

borishaifa [10]

If the impulse is 25 N-s, then so is the change in momentum.
The mass of the ball is extra, unneeded information.

Just to make sure, we can check out the units:

Momentum = (mass) x (speed) = kg-meter / sec

Impulse = (force) x (time) = (kg-meter / sec²) x (sec) = kg-meter / sec

3 0

3 years ago

Read 2 more answers

An electron moving with a velocity = 5.0 × 107 m/s enters a region of space where perpendicular electric and a magnetic fields a

Cloud [144]

Answer:

magnetic field will allow the electron to go through 2 x $10^{4}$ T k

Explanation:

Given data in question

velocity = 5.0 × $10^{7}$

electric filed = $10^{4}$

To find out

what magnetic field will allow the electron to go through, undeflected

solution

we know if electron move without deflection i.e. net force is zero on electron and we can say both electric and magnetic force equal in magnitude and opposite in directions

so we can also say

F(net) = Fe + Fb i.e. = 0

q V B + q E = 0

q will be cancel out

$10^{4}j$ + 5e + 7i × B = 0