Which of the following statements are true?

Physics

2 answers:

Verizon [17]3 years ago

8 0

'B' and 'C' are both true.

e-lub [12.9K]3 years ago

8 0

B. Energy as heat flows from a higher temperature to a lower temperature.

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When looking at the chemical symbol, the charge of the ion is displayed as the

Black_prince [1.1K]

Answer:

superscript

Explanation:

When looking at the chemical symbol, the charge of the ion is displayed as the Superscript. This is because the charge of ions is usually written up on the chemical symbol while the atom/molecule is usually written down the chemical symbol. The superscript refers to what is written up on the formula while the subscript is written down on the formula.

An example is H2O . The 2 present represents two molecule of oxygen and its written as the subscript while Fe2+ in which the 2+ is written up is known as the superscript.

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3 years ago

What did Newton's book Mathematical Principles of Natural Philosophy argue about the role of mathematics in understanding the na

quester [9]

"Newton's book argued that mathematical principles could be applied to our understanding of the natural world" is what <span>Newton's book Mathematical Principles of Natural Philosophy argue about the role of mathematics in understanding the natural world. The correct option among all the options that are given in the question is the last option or option "D". I hope the answer has come to your help.</span>

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2 years ago

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Consider the sections of two circuits illustrated above. Select True or False for all statements. After connecting c and d to a

Basile [38]

Answer:

Follows are the solution to the given question:

Explanation:

In this question the missing file of the circuit is not be which is defined in attached file please find it.

In Option 1, this statement is true because the current is on $R_3 \ and \ R_4$ , that is the same.

In option 2, this statement is false because $Rcd=R_3+R_4$ therefore it implies that Rcd is always larger then $R_3$ .

In option 3, this statement is true because the voltage of $R_1 \ and \ R_2$ is always equal.

In option 4, this statement is true because $Rab= \frac{1}{(\frac{1}{R1}+\frac{1}{R2})}=\frac{R1R2}{(R1+R2)}. \frac{R2}{(R1+R2)}$ is always smaller then 1 therefore, $R_1 \times (\frac{R2}{(R1+R2)})$ is always equal to R1.