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3 years ago

Why is it more helpful to know a tornadoes velocity rather than its speed

Physics

2 answers:

max2010maxim [7]3 years ago

6 0

So you know where the tornado is going

victus00 [196]3 years ago

5 0

So you not only know<span> how fast it is going, but where it is going.</span>

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The amount of charge that passes through the filament of a certain lightbulb in 2.00 s is 1.67 C. If the current is supplied by

Artemon [7]

Answer:

E = 20.03 J

Explanation:

Given that,

The amount of charge that passes through the filament of a certain lightbulb in 2.00 s is 1.67 C,

Voltage, V = 12 V

We need to find the energy delivered to the lightbulb filament during 2.00 s.

The energy delivered is given by :

$E=I^2Rt$ . ....(1)

As,

$I=\dfrac{q}{t}\\\\I=\dfrac{1.67}{2}\\\\I=0.835\ A$

As per Ohm's law, V = IR

$R=\dfrac{V}{I}\\\\R=\dfrac{12}{0.835}\\\\R=14.37\ \Omega$

Using formula (1).

$E=0.835^2\times 14.37\times 2\\\\=20.03\ J$

So, the energy delivered to the lightbulb filament is 20.03 J.

6 0

3 years ago

You measure an electric field of 1.36×106 N/C at a distance of 0.158 m from a point charge. There is no other source of electric

marysya [2.9K]

Answer:

The Electric flux will be $0.42\times10^6\ \rm N.m^2/C$

Explanation:

Given

Strength of the Electric Field at a distance of 0.158 m from the point charge is

$E=1.36\times10^6\ \rm N/C$

We know that the flux of the Electric Field can be calculated by using Gauss Law which is given by

$\int E.dA=\dfrac{q_{in}}{\epsilon_0}\\$

Let consider a sphere of radius 0.158 m as Gaussian Surface at a distance of 0.158 m from the point charge and Let $\phi$ be the flux of the Electric Field coming out\passing through it which is given by

$\phi=\int E.dA=1.36\times10^6 \times4\pi \times 0.158^2\\\\=0.42\times10^6\ \rm N.m^2/C$

It can be observed that same amount of flux which is passing through the Gaussian sphere of radius 0.158 is also passing through the Gaussian sphere of radius 0.142 m at a distance of 0.142 m from its centre.

Also it can be observed that the charge inside the two Gaussian Sphere mentioned have same value so the Flux of electric field through them will also be same.

So the electric flux through the surface of sphere that has given charge at its centre and that has radius 0.142 m is $0.42\times10^6\ \rm N.m^2/C$

8 0

3 years ago

Organism undergo constant chemical changes as they maintain an internal balance known as?

Aleks04 [339]

The answer is homeostasis.

3 0

3 years ago

Read 2 more answers

A pursuit spacecraft from the planet Tatooine is attempting to catch up with a Trade Federation cruiser. As measured by an obser

madam [21]

Answer:

the speed of the cruiser relative to the pursuit ship is 0.3846c

Explanation:

the solution is in the attached Word file

Download docx

3 0

3 years ago

Read 2 more answers

Two long, parallel wires each carry the same current I, but the two currents are anti-parallel. The two wires are a distance r a

Georgia [21]

Answer:

8 x 10⁻⁷ x I / r

Explanation:

Two parallel long wires are carrying current I . Let the direction be towards the right in the farthest and towards the left in the nearest. Magnetic field due to current I at a distance d is given by the expression

B = μ₀ 2 I / 4π d

I the present case distance d = r/2

Magnetic field due to one wire at point d = r/2 is

B₁ = μ₀ 2 I / (4π r / 2 )

= 10⁻⁷ x 4I / r

Magnetic field due to the other wire at point d = r/2 is

B₂ = μ₀ 2 I / (4π r / 2 )

= 10⁻⁷ x 4I / r

Direction of magnetic field due to both the wires at the mid point P will be same . It will be in downward direction in the given scenario

So total magnetic field

B = B₁ + B₂

= 2 x 10⁻⁷ x 4I / r

= 8 x 10⁻⁷ x I / r

6 0

3 years ago