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JulsSmile [24]
3 years ago
14

Why is it more helpful to know a tornadoes velocity rather than its speed

Physics
2 answers:
max2010maxim [7]3 years ago
6 0
So you know where the tornado is going
victus00 [196]3 years ago
5 0
So you not only know<span> how fast it is going, but where it is going.</span>
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This is for physical science. Can someone help me?
Radda [10]
A. 320 g
B. 160 g
C. 80 g
D. 40 g
6 0
3 years ago
Read 2 more answers
A horse runs around a circular track that is 350.0 m long. He runs clockwise from
Ivahew [28]

Answer:

A 0m

Explanation:

The horse runs clockwise round the strack, then goes back to the start line ending up back at the same place when it started.

5 0
3 years ago
Read 2 more answers
Fg =G m1m2/r2 solver for G
Blababa [14]

G = \frac{F_{g} r^{2}  }{m_{1} m_{2}  }

Explanation:

 Solving for G simply implies that we make G the subject of the formula:

  Given equation:

               F_{g} = G \frac{m_{1}  m_{2} }{ r^{2} }

 To make G the subject of this expression follow these steps:

            Multiply both sides of the equation by r^{2}

   

     F_{g} x r^{2} = G \frac{m_{1}  m_{2} }{ r^{2} } x r^{2}

 

      This gives:

                F_{g}  r^{2} = G m_{1}  m_{2}

     

    Multiply both sides by \frac{1}{m_{1} m_{2} }

  F_{g}  r^{2}  x   \frac{1}{m_{1} m_{2} } =  \frac{1}{m_{1} m_{2} } x G m_{1}  m_{2}

  Therefore:

                G = \frac{F_{g} r^{2}  }{m_{1} m_{2}  }

Learn more:

Solving formula brainly.com/question/2998489

#learnwithBrainly

6 0
3 years ago
He sees a mouse sniffing along at 0.2 m/s but it hears and starts to scurry for safety. In just 4.7 s it speeds up to 1.6 m/s. F
NISA [10]

Answer:

0.30 m/s²

Explanation:

Given:

v₀ = 0.2 m/s

v = 1.6 m/s

t = 4.7 s

Find: a

a = (v − v₀) / t

a = (1.6 m/s − 0.2 m/s) / 4.7 s

a = 0.30 m/s²

8 0
3 years ago
A thin, uniform rod is hinged at its midpoint. to begin with, one-half of the rod is bent upward and is perpendicular to the oth
bazaltina [42]
<span>Answer: initial I = (m/2)L²/3 + (m/2)L² where L = ½ the length of the rod, and the vertical half can be treated as a point mass. initial I = mL²(1/6 + 1/2) = 2mL²/3 final I = m(2L)²/3 = 4mL²/3 Since I has doubled and momentum is conserved, ω has halved. ω = 3.9 rad/s. Formulaically: 2mL²/3 * 7.8rad/s = 4mL²/3 * ω</span>
5 0
3 years ago
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