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3 years ago

CAN ANYONE PLEASE HELP MY BOOKS ARENT HELPING!!!! THIS IS FOR FIRE TECH

Chemistry

1 answer:

Mazyrski [523]3 years ago

5 0

Answer:

The answer to the question is;

The occupant load of the store having a floor area of 100,000 ft² is 3,317.86 persons.

Explanation:

Based on NFPA guidelines we have for sales on street floor, the allowable occupant load factor per person is 30 ft²

That is where the floor area is 100,000 square feet we have the number of allowable occupant given by

(100,000 ft²)/(30 ft²/Person) = $\frac{10000}{3} Persons$ or 3,333 persons

That is the occupant load of the store if the floor area is 100,000 square feet = 3,333 persons

Based on m² we have 9,290 m² will require 2.8 m²/person

which gives;

(9,290 m²)/(2.8 m²/person) = $\frac{9290}{2.8} Persons$ = 23225/7 or 3,317.86 persons

Therefore applying safety, we go with the lesser number and we have

The occupant load of the store having a floor area of 9,290 m² = 3,317.86 persons.

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PLeaseee ITS Timedddd + BrainlIESTT

zmey [24]

Answer:

d. 12.3 grams of Al2O3

Explanation:

Based on the reaction:

4Al + 3O2 → 2Al2O3

<em>Where 4 moles of Al reacts in excess of oxygen to produce 2 moles of aluminium oxide.</em>

<em />

To solve this question we must find the moles of Aluminium. With these moles we can find the moles of aluminium oxide using the reaction:

<em>Moles Al -Molar mass: 26.9815g/mol-</em>

6.50g * (1mol / 26.9815g) = 0.241 moles Al

<em>Mass Al₂O₃ -Molar mass: 101.96g/mol-</em>

0.241 moles Al * (2 mol Al2O3 / 4 mol Al) = 0.120 moles Al2O3

0.120 moles Al2O3 * (101.96g / mol) =

12.3g of Al2O3 are produced.

Right answer is:

<h3>d. 12.3 grams of Al2O3 </h3>

8 0

3 years ago

What is the correct formula that would result from the combination of the two ionic species?

Soloha48 [4]

Answer:

CsCl

Explanation:

The ionic species are:

Cs⁺ and Cl⁻

6 0

2 years ago

There are two naturally occurring isotopes of copper. 63cu has a mass of 62.9296 amu. 65cu has a mass of 64.9278 amu. determine

SSSSS [86.1K]

1) You need to use the atomic mass of copper.

You can find it in a periodic table. It is 63.546 amu.

2) The atomic mass is the weigthed mass of the different isotopes.

This is, the atomic mass of one element is the atomic mass of each isotope times its corresponding abundance:

=> atomic mass of the element = abundance isotope 1 * atomic mass isotope 1 + abundance isotope 2 * atomic mass isotope 2 + ....+abundance isotope n * atomic mass isotope n.

3) The statement tells there are two isotopes so the abundance of one is x and the abundance of the other is 1 - x

=> 63.546 amu = x * 62.9296 amu + (1-x)*64.9278

=> 63.546 = 62.9296x + 64.9278 - 64.9278x

=> 64.9278x - 62.9296 = 64.9278 - 63.546

=> 1.9982x = 1.3818

=> x = 1.3818 / 1.9982 = 0.6915 = 69.15%

=> 1 - x = 1 - 0.6915 = 0.3085 = 30.85%

Answer:

Cu-63 69.15%;

Cu-65 : 30.85%

3 0

3 years ago

For the vaporization of a liquid at a given pressure: A.ΔG is positive at all temperatures. B.ΔG is negative at all temperatures

MArishka [77]

Answer:

C. ΔG is positive at low temperatures, but negative at high temperatures (and zero at some temperature).

Explanation:

Since we need to give energy in the form of heat to vaporize a liquid, the enthalpy is positive. In a gas, molecules are more separated than in a liquid, therefore the entropy is positive as well.

Considering the Gibbs free energy equation:

ΔG= ΔH - TΔS

+ +

When both the enthalpy and entropy are positive, the reaction proceeds spontaneously (ΔG is negative) at high temperatures. At low temperatures, the reaction is spontaneous in the reverse direction (ΔG is positive).

5 0

3 years ago

If you set up an experiment with two different independent variables, then the results would be_____.

MariettaO [177]

Answer: A) Inconclusive; you would not know which of the two variables caused the change.

Explanation:

When you set up an experiment, you must make sure that you control the variables such that only one independent variable changes at a time, while all the remainder conditions (the other independent variables) are controlled (fixed).

By observing (measuring) the dependent variable, while only one independent variable changes you can understandhow such independent variable explains (determines) the dependent variable, leading to a conclusion.

Conversely, if two or more independent variables change at a time, then there is no way that you can tell how the output (dependent variable) is related with one or other of the changes of the indipendent variables. You wolud not be able to discriminate (distinguish) the effect of one or other variable, making the experiment inconclusive

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4 0

3 years ago