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inysia [295]
3 years ago
8

CAN ANYONE PLEASE HELP MY BOOKS ARENT HELPING!!!! THIS IS FOR FIRE TECH

Chemistry
1 answer:
Mazyrski [523]3 years ago
5 0

Answer:

The answer to the question is;

The occupant load of the store having a floor area of 100,000 ft² is 3,317.86 persons.

Explanation:

Based on NFPA guidelines  we have for sales on street floor, the allowable occupant load factor per person is 30 ft²

That is where  the floor area is 100,000 square feet we have the number of allowable occupant given by

(100,000 ft²)/(30 ft²/Person) = \frac{10000}{3} Persons or 3,333 persons

That is the  occupant load of the store if the floor area is 100,000 square feet = 3,333 persons

Based on m² we have  9,290 m² will require 2.8 m²/person

which gives;

(9,290 m²)/(2.8 m²/person) = \frac{9290}{2.8} Persons = 23225/7 or 3,317.86 persons

Therefore applying safety, we go with the lesser number and we have

The occupant load of the store having a floor area of 9,290 m² = 3,317.86 persons.

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