The temperature,internal energy,and kinetic energy will all increase
Answer:
T2 = 51.6°C
Explanation:
Given:
P1 = 1.01 atm
T1 = 25°C + 273 = 298K
P2 = 1.10 atm
T2 = ?
P1/T1 = P2/T2
Solving for T2,
T2 = (P2/P1)T1
= (1.10 atm/1.01 atm)(298K)
= 324.6 K
= 51.6°C
where Tc = Tk - 273
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Answer:
Mass = 88.12 g
Explanation:
Given data:
Mass of iron oxide = 126 g
Mass of iron formed = ?
Solution:
Chemical equation:
Fe₂O₃ + 3CO → 2Fe + 3CO₂
Number of moles of iron oxide:
Number of moles = mass/molar mass
Number of moles = 126 g/ 159.69 g/mol
Number of moles = 0.789 mol
Now we will compare the moles of iron with iron oxide.
Fe₂O₃ : Fe
1 : 2
0.789 : 2/1×0.789 = 1.578 mol
Mass of iron:
Mass = number of moles ×molar mass
Mass = 1.578 mol × 55.84 g/mol
Mass = 88.12 g
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